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tatiyna
3 years ago
10

Energy = Force x Distance. Gravitational potential energy = Force (weight) x Height of the object above the ground. If a waterme

lon weighs 98 Newtons and sits on a shelf 10 meters above the floor, how much gravitational potential energy does it have in Joules?
Advanced Placement (AP)
1 answer:
alukav5142 [94]3 years ago
7 0

Answer:

980

Explanation:

weight×height=gravitational potential energy

98×10=980

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For time t≥0 , the acceleration of an object moving in a straight line is given by a(t)=sin(t23). what is the net change in velo
Firlakuza [10]

The net change in velocity during the given time interval is equal to -0.665.

<u>Given the following data:</u>

  • Initial time = 0.75 seconds.
  • Final time = 2.25 seconds.
  • Acceleration, a(t) = sin(\frac{t^2}{3} )

<h3>How to calculate the net change in velocity.</h3>

Since acceleration is the rate of change of velocity of an object, we would derive an expression for the velocity by differentiating with respect to time:

V(t) = \frac{d}{dt} a(t)\\\\V(t) = \frac{d}{dt} (sin(\frac{t^2}{3} ))\\\\V(t) =  cos( \frac{t^2}{3})(\frac{2t}{3})\\\\V(t) = \frac{2t}{3}cos( \frac{t^2}{3})

Substituting the time interval, we have:

V(t) = \frac{2\times 2.25}{3}cos( \frac{2.25^2}{3})- \frac{2\times 0.75}{3}cos( \frac{0.75^2}{3})\\\\V(t) = \frac{4.5}{3}cos( \frac{5.0625}{3})- \frac{1.5}{3}cos( \frac{0.5625}{3})\\\\V(t) =1.5(-0.11643)-0.5(0.98247)

V(t) = -0.665.

Read more on acceleration here: brainly.com/question/24728358

6 0
2 years ago
4. Suppose the house in question 3 is located in Cleveland where the annual average solar flux is 160 W/m2 2. If 10 m2 of solar
Ahat [919]

Answer:

Solar flux that incident on it is given as

S = 160 W/m/m

Now we know that the area of solar panels is given as

A = 10 m^2

So total solar power received by solar panels is given as

Power Received = (Solar flux) \times (Area)PowerReceived=(Solarflux)×(Area)

P = S\times AP=S×A

now here we have

P = 160 \times 10P=160×10

P = 1600 WP=1600W

now we know that efficiency of the solar panels is 20%

so total output power will be

efficiency = \frac{P_{out}}{P_{in}}efficiency=

P

in

P

out

0.20 = \frac{P_{out}}{1600}0.20=

1600

P

out

P_{out} = 320 WP

out

=320W

3 0
3 years ago
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