Find the discriminant of the equation. x2 + 3x - 4 = 0 -7 25 -4 1

What is the HCF and LCM of 268 and 244

Ray Of Light [21]

Answer:

HCF = 4

LCF = 16348

HOPE THIS HELPS :)

5 0

3 years ago

A chemist has two alloys, one of which is 5% gold and 20% lead and the other which is 30% gold and 50% lead. How many grams of e

dmitriy555 [2]

The amount of the first alloy is 450 grams and the amount of the second alloy is 30 grams.

<h3>What is a linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have:

A chemist has two alloys, one of which is 5% gold and 20% lead and the other which is 30% gold and 50% lead.

Let's suppose the x is the amount of the first alloy and y is the amount of the second alloy:

We can make two linear equation in two variables:

0.05x + 0.3y = 31.5 ...(1)

0.2x + 0.5y = 105 ...(2)

After solving the above two linear equations by substitution method, we get:

x = 450 grams

y = 30 grams

Thus, the amount of the first alloy is 450 grams and the amount of the second alloy is 30 grams.

Learn more about the linear equation here:

brainly.com/question/11897796

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3 0

2 years ago

Please check these please

antoniya [11.8K]

-5x=60

The first thing we want to do is to divide -5 on both sides. We do this because -5x, is the same as -5 times x and we want to do the inverse of that.

After we divide on both sides, we get x=60/-5

We know that 60 divided by -5 is -12.

Therefore our answer is: x=-12

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5= n + 2

We always want to get the variable to be alone, so if we subtract by 5 we would be doing the opposite of getting the variable alone. Although, if we subtract by 2 on both sides, we would get the variable alone and the answer would be 3=n

Therefore our answer is: False

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2(x-7)

By looking at this question, we see x being subtracted by 7. Then we see that 2 is being multiplied to that.

Therefore our answer is: C

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The product of a number and 4 increased by 8

In these types of questions, it's smart to break it up. We will start with the product of a number and 4. We know that a number is a variable and if we look at the multiple choice answers we can see that the variable they chose to use is n. We also know that a product is when numbers get multiplied. So that means 4 and n get multiplied which turns into 4n.

For the other part of the problem, we know that increased by 8 means added my 8. Now that we got our answers, we put then together.

Therefore our answer is: A 4n+8

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Pls give a like if this helped you!!!

4 0

2 years ago

Read 2 more answers

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30 What score is necessary to reach

nlexa [21]

Answer:

A score of 150.25 is necessary to reach the 75th percentile.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.

This means that $\mu = 130, \sigma = 30$

What score is necessary to reach the 75th percentile?

This is X when Z has a pvalue of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 130}{30}$

$X - 130 = 0.675*30$

$X = 150.25$

A score of 150.25 is necessary to reach the 75th percentile.

7 0

3 years ago

Expressions cannot _____.

Gwar [14]

Expressions cannot be solved.
Although they are similar to equations, you can solve an equation, but you cannot solve an expression. You can evaluate it, simplify it, and it can have many variables, however, an expression just exists, it is not a problem that has to be solved.

8 0

3 years ago

Read 2 more answers