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4 years ago

The fraction 12/20 express in its simplest form is:

Mathematics

2 answers:

goldfiish [28.3K]4 years ago

8 0

Divided both of the numbers by 4, and you get the fraction of 3/5

mash [69]4 years ago

8 0

The answer is 3/5. 4 can go into both 12 and 20.

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What are the domain and range of the function

8_murik_8 [283]

The domain of a function is the X values
The range of a function is the Y values

8 0

4 years ago

Characteristics of LCM

exis [7]

The LCM (least common multiple) is the smallest positive whole number exactly divisible by two or more given whole numbers.

5 0

4 years ago

Are these two ratios proportional <br> 3/5 &10/6

fomenos

First off, let's find the LCM of both 5 and 6 to easily compare.

LCM = 30

3/5 = 18/30
10/6 = 50/30

18 $\neq$ 30

These ratios aren't proportional. Hope this helps!

4 0

3 years ago

Read 2 more answers

Find the solution of the initial value problem y Superscript prime prime Baseline plus 4 y Superscript prime Baseline plus 5 y e

sergiy2304 [10]

Answer:

$y(t) = - 5 {e}^{2\pi - 2t} \cos(t)$

Step-by-step explanation:

The given initial value problem is

$y''+4y'+5=0$

$y( \frac{ \pi}{2} ) = 0$

$y'( \frac{ \pi}{2} ) = 5$

The corresponding characteristic equation is

${m}^{2} + 4m + 5 = 0$

$m = - 2 \pm \: i$

The general solution becomes:

$y(t) = A {e}^{ - 2t} \cos(t) + B {e}^{ - 2t} \sin(t)$

We differentiate to get:

$y'(t) = - A {e}^{ - 2t} \sin(t) - 2 A {e}^{ - 2t} \cos(t) + B {e}^{ - 2t} \cos(t) - 2B {e}^{ - 2t} \sin(t)$

We apply the initial conditions to get;

$y( \frac{\pi}{2} ) = A {e}^{ - 2\pi} \cos( \frac{\pi}{2} ) + B {e}^{ - 2\pi} \sin( \frac{\pi}{2} )$

$A {e}^{ - 2\pi} (0 ) + B {e}^{ - 2\pi} ( 1) = 0$

$B = 0$

Also;

$y'( \frac{\pi}{2} ) = - A {e}^{ - 2\pi} \sin( \frac{\pi}{2} ) - 2 A {e}^{ - 2\pi} \cos( \frac{\pi}{2} ) + B {e}^{ - 2\pi} \cos( \frac{\pi}{2} ) - 2B {e}^{ - 2\pi} \sin( \frac{\pi}{2} )$