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Rama09 [41]
3 years ago
7

What is the answer to this question

Mathematics
2 answers:
ELEN [110]3 years ago
8 0
K^2 + 4kn - 96
= (k + 12n)(k - 8n)

x^2 + 5xy -14y^2
= (x - 2y)(x + 7y)
PIT_PIT [208]3 years ago
6 0
(K+12n)(k-8n)
.............
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How do I do this? It is a regular hexagon with a height of 30. We have to find the perimeter of it.
Sliva [168]

Answer:

The radius of a hexagon is called the apothem, which in this case is 15.

We need to know the side length which is found by the equation:

side length = apothem * 2 * (tan (180 / #sides))

side length = apothem * 2 * (tan (180 / 6))

side length = 15 * 2 * (tan (30 degrees))

side length = 30 * .57735

side length = 17.3205

We need the perimeter of the hexagon which equals the side length times six.

perimeter = 6 * 17.3205 = 103.923

Source: https://www.1728.org/polygon.htm

Step-by-step explanation:

8 0
4 years ago
PLEASE ANSWER ASAP WILL GIVE BRAINLIEST!!!!!!!!
Alex Ar [27]

Answer: c. is corect

hope this helps

3 0
3 years ago
Read 2 more answers
Ms. Lunette has 18 students in her class. She wants to send 3 of these students to pick up books for the class.
tigry1 [53]

The number of possible combinations is given by

... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations

_____

There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.

7 0
4 years ago
-2(x+2=x-3(x+1)-1 please help me
Tcecarenko [31]
The solution would be x=0 because the statement is false.
7 0
3 years ago
Find tan 0.<br> (Marking brainliest if correct) <br><br> 8/17<br> 15/17<br> 15/8<br> 8/15
Rina8888 [55]

Answer:

15/8

Step-by-step explanation:

Assuming you mean tan theta

Tan(theta) = opposite/adjacent

We know the adjacent side is 8 so the bottom of the fraction must also be 8

C: 15/8 is the only option that fits this criteria

4 0
3 years ago
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