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Tema [17]
3 years ago
9

The zeros of a quadratic function are -8 and 5. Write the quadratic function in Standard Form.

Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

y = x² + 3x - 40

Step-by-step explanation:

Given the zeros are x = - 8 and x = 5, then the factors are

(x + 8) and (x - 5) and

y = (x + 8)(x - 5) ← expand factors

y = x² - 5x + 8x - 40, hence

y = x² + 3x - 40 ← in standard form

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1) Graph the following lines and using the graph determine several values of x for which the graph is positive (negative):
Aleksandr [31]

1) y=-0.5x-2


The graph of the above equation is attached in the attachment below.  

For all the values from negative infinity to -4, the function is positive.  

X ∈ (-∞,-4]


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To find the y- intercept, plug x=0  

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Y- intercept = (0,13)


x- intercept = (13,0)


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Area = \frac{169}{2} sq unit.


4) The graphs of y=-2x+7 and y=0.5x-5.5 is attached in the attachment below.  

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5) A = (-3,0)


B = (4,5)


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Slope intercept of line y=mx+b


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0=\frac{5(-3)}{7} +b

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Equation of line AB: y=\frac{5x}{7} +\frac{15}{7}


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Equation of line AC = y=\frac{-4x}{3} -4


Y intercept of AB = (0,\frac{15}{7} )




5 0
3 years ago
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jarptica [38.1K]

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