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marishachu [46]
4 years ago
11

I need some help with this answer :))))

Mathematics
2 answers:
sdas [7]4 years ago
7 0
The answer is 7/44, because when you multiply fractions, you multiply both of the numerators together, and both of the denominators together. Multiplying 7*1 is 7, and 4*11 is 44. So, the numerator is 7 and the denominator is 44. There isn’t a whole number factor for both 44 and 7, so they’re already in their simplest form.
scZoUnD [109]4 years ago
3 0

Step-by-step explanation:

\frac{7}{11}  \times  \frac{1}{4}  =  \frac{7 \times 1}{11 \times 4}  =  \frac{7}{44}  \\

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Solve the system of equations by substitution. Simplify your answer. Write the
pychu [463]

Answer:

x = 5     y = 2

Step-by-step explanation:

3x + 2(3x - 13) = 19

3x + 6x - 26 = 19

9x = 45

x = 5

y = 3(5) - 13

y = 15 - 13

y = 2

4 0
3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
A.) write an equation in slope intercept form for the total cost of any number of tickets at 7 tickets for $5.
MrMuchimi
Slope intercept form is y = mx + b

7 tickets for $5 means that 1 ticket costs 5/7 dollars

So for part a, the slope intercept form would be:

y = \frac{5}{7}x

where x is the number of tickets, and y is the price.

For part b)

The slope intercept form is:
y = 25x

where x is the number of all you can ride wristbands you buy, and y is the total price.

7 0
3 years ago
Can someone help me solve these two questions please
Vaselesa [24]

Answer:

hope this help

Step-by-step explanation:

sorry..I send pic instead..hope this help

4 0
3 years ago
What all does the ASA postulate involve
ZanzabumX [31]

Answer:

ASA means Angle-Side-Angle

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Step-by-step explanation:

7 0
4 years ago
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