All categories

3 years ago

Does -2(11-12x)=-4(1-6x) does it have one solution or no solution or many solutions

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

6 0

Answer:

no solutions

Step-by-step explanation:

-2(11-12x)=-4(1-6x)

Distribute

-22 +24x = -4 +24x

Subtract 24x from each side

-22 +24x-24x = -4 +24x-24x

-22 = -4

This is never true, so there are no solutions

You might be interested in

I need help please, I will give brainliest to the first person that answers. Also extra points.

Papessa [141]

Answer:

a + c = 7

9a + 4c = $43

Step-by-step explanation:

There're 7 tickets which were bough in total. Two different types of tickets, one which represented children, the other for adults. The adult ticket is represented by a and is 9 dollars. The children's ticket is represented by c and is 4 dollars.

Have a nice April Fool's XD.

5 0

3 years ago

What is the area of the figure below? 7.5m^2 15m^2 21.25m^2 42.5m^2

Novay_Z [31]

The answer is c!!! hope this helps!!!

7 0

3 years ago

Read 2 more answers

What is the measure of x in degrees ?

mr Goodwill [35]

Answer:

x = 35°

Step-by-step explanation:

Same side interior angles are supplementary, or they add up to 180°. So write an equation:

$x+145=180$

Solve for x. Subtract 145 from both sides:

$x+145-145=180-145\\\\x=35$

The value of x is 35°.

:Done

8 0

3 years ago

Consider the limit of rational function p(x)l q(x)

Helga [31]

$\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{0}{1}=0$

The limit tends to 0
Hence c=0

$\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to c}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{1}=1$

Here limit tends to 1
Hence c=1

$\\ \sf\bull\dashrightarrow {\displaystyle{\lim_{x\to 0}}}\dfrac{p(x)}{q(x)}=\dfrac{1}{0}=\infty$

Here x tends to infty.
c=infty

For the fourth one limit also tends to zero

8 0

3 years ago

Khaleej Times)Petrol prices in the UAE have jumped over 56 per cent since January 2022 due to an increase in global crude oil pr

Paraphin [41]

Answer:

it will equal1to indequate it

8 0

2 years ago