Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Answer:
3-11n>21-5n
Step-by-step explanation:
It seems right, so hopefully it is.
Answer:
x=5
Step-by-step explanation:
so to isolate the x you dived the -3 to both sides
so it will now be
x=5 because a negative times or divided by a negative equals a positive so to prove that x=5
-3(5)=-15
which is true
Answer:(-3,-1.5)
Step-by-step explanation: the vertex is the point then the line starts to bend. that would be (-3,-1.5).
Answer: 120
"A analog clock is diveded up into 12 sectors, based on the numbers 1-12. one sector represents 30 degrees (360/12=30). if the hour hand is directly on the 10, and the minute hand is on the 2, that means there are 4 sectors of 30 degree between then, thus they are 120 degree apart (30*4=120)."
