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Mice21 [21]
3 years ago
9

I don’t get this work I can’t solve it

Mathematics
2 answers:
AnnyKZ [126]3 years ago
6 0

Answer:

Step-by-step explanation: the answer is -13, first you take the multiplication part so 1 times -6 and that’s -6, and the you take it in the correct order from left to right as usual, first -7+ 1 to get -6 and then + -1 to get -7. Then you take -7+ -6 and that’s - 13

Darina [25.2K]3 years ago
3 0

Answer:

0

Step-by-step explanation:

-7+1+ -1 * -6

Using PEMDAS, we multiply and divide first

-1*-6 = 6

Then we add and subtract from left to right

-7+1+ 6

-6+6 =0

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larisa86 [58]
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<span>
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8 0
3 years ago
Read 2 more answers
LCM of x&lt;sup&gt;2&lt;/sup&gt;+5x+6 and x&lt;sup&gt;2&lt;/sup&gt;-x-6 is ………………………
sergejj [24]

Answer:

(x^2 - 9)(x + 2)

Step-by-step explanation:

Given:

x^2 + 5x + 6

x^2 - x - 6

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

x^2 + 5x + 6

x^2 + 3x + 2x + 6

(x^2 + 3x) + (2x + 6)

x(x + 3) + 2(x + 3)

(x + 2)(x + 3)

x^2 - x - 6

x^2 - 3x +2x - 6

x(x - 3) + 2(x - 3)

(x + 2)(x - 3)

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

x^2 + 5x + 6 = (x + 2)(x + 3)

x^2 - x - 6 = (x + 2)(x - 3)

The common factors would be: =>

(x + 2) (this is common in both polynomials, so we would take just one of them as a factor.

(x + 3) and,

(x - 3)

Their product = (x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)

4 0
4 years ago
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ad-work [718]
C = 1/4 y + -1/4 is the answer
5 0
3 years ago
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Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with mean 1/0.41/0
lbvjy [14]

Answer:

a) P(t>3)=0.30

b) P(t>10|t>9)=0.67

Step-by-step explanation:

We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.

The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.

The probabity that a repair time exceeds k hours can be written as:

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(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?

The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.

In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.

P(t>10|t>9)=P(t>1)

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6 0
3 years ago
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