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kkurt [141]
3 years ago
5

The point (-7, -24) is on the terminal ray of angle θ which is in standard position. A student found the six trigonometric value

s for angle θ. The student’s answers are shown. sin (theta) = StartFraction 24 Over 25 EndFraction. cosine (theta) = negative seven-twenty-fifths.
tangent (theta) = negative twenty-four-sevenths. cosecant (theta) = StartFraction 25 Over 24 EndFraction.

secant (theta) = negative StartFraction 25 Over 7 EndFraction.

cotangent (theta) = negative StartFraction 7 Over 24 EndFraction.

Which value(s) are incorrect?

sin(0)
cos(0)
tan(0)
csc(0)
sec(0)
cot(0)
Mathematics
2 answers:
trapecia [35]3 years ago
5 0

Answer:

Sine(0) Tangent(0) Co-secant(0) Cotangent(0)

Step-by-step explanation:

Just took it

Delicious77 [7]3 years ago
4 0

Answer:

The \sin \theta, \tan \theta, \csc \theta, \cot \theta have the wrong values.

Step-by-step explanation:

The point (-7,-24) lies in the third quadrant, where the only tangent function will have a positive value and all the other trigonometric functions are negative.

The origin has a distance from the point is \sqrt{(- 7)^{2} + (- 24)^{2}} = 25.

If the point makes an angle \theta with the negative x-axis, then

\sin \theta = - \frac{24}{25}

\cos \theta = -\frac{7}{25}

\tan \theta = \frac{24}{7}

\sec \theta = - \frac{25}{7}

\csc \theta = - \frac{25}{24}

\cot \theta = \frac{7}{24}

Therefore, the \sin \theta, \tan \theta, \csc \theta, \cot \theta have the wrong values. (Answer)

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Answer: F=15N


Step-by-step explanation:

1. You know that the force acting on the object varies directly with the object's acceleration. Then, by definition, you have:

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