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Doss [256]
2 years ago
11

What is 4-2x+8+5x simplified

Mathematics
2 answers:
sveta [45]2 years ago
6 0

Answer: it is 3 • (x + 4)

Step-by-step explanation: We move all terms to the left:

4-2x+8-(+5x)=0

We add all the numbers together, and all the variables

-2x-(+5x)+12=0

We get rid of parentheses

-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7We move all terms to the left:

4-2x+8-(+5x)=0

We add all the numbers together, and all the variables

-2x-(+5x)+12=0

We get rid of parentheses

-2x-5x+12=0

We add all the numbers together, and all the variables

-7x+12=0

We move all terms containing x to the left, all other terms to the right

-7x=-12

x=-12/-7

x=1+5/7

Artemon [7]2 years ago
6 0
4-2x+8+5x
-2x -2x
4 + 8 + 3x
12 + 3x
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In a survey, 540 people, or 80%, said they attended a movie at least once a month. How many people were surveyed?
Deffense [45]
X = total amount of people

80% of x = 540
.8x = 540
x = 675

There were 675 people
8 0
3 years ago
Can someone please help me, Thanks - Alyssa T.
Oxana [17]
A=LW
192=(13+x)((9+x)
192=117+22x+x^2 (subtract 192 from both sides)
x^2+22x-75+0 (factor)
(x+25)(x-3)=0
so x=-25 or 3
Check work
since we are adding x it can only be the positive solution so x=3 so the new dimensions are:
L=13+3=16m
W=9+3=12
check: 16*12=192 so the answer is correct hope this helped
7 0
3 years ago
A non-Newtonian liquid demonstrates properties of both a solid and a liquid. A recipe for a non-Newtonian liquid calls for 1 cup
Nadya [2.5K]
In total 15 cups of water
7 0
2 years ago
*Find the formula of the series 1+2²+3²+4²+....+n²*<br>​
Sophie [7]

The formula is \frac{n(n+1)(2n+1)}{6}

What are series?

In mathematics, we can describe a series as adding infinitely many numbers or quantities to a given starting number or amount.

We will find the formula as shown as below:

Let S=1+2^2+3^2+4^2+................+n^2

We know (n+1)^3=n^3+3n^2+3n+1

(1+1)^3=1^3+3(1)^2+3(1)+1

(2+1)^3=2^3+3(2)^2+3(2)+1

(3+1)^3=3^3+3(3)^2+3(3)+1

.

.

(n+1)^3=n^3+3(n)^2+3(n)+1

On adding

2^3+3^3+4^3......(n+1)^3=(1^3+2^3+3^3+.....+n^3)+3(1^2+2^2+.....+n^2)+3(1+2+3....n)+(1+1+1+....+1)

2^3+3^3+4^3......(n+1)^3-(1^3+2^3+3^3+.....+n^3)=3S+\frac{3n(n+1)}{2}+(1+1+1+....+1)

(n+1)^3-1^3=3S+\frac{3n(n+1)}{2} +n

n^3+3(n)^2+3(n)+1-1=3S+\frac{3n(n+1)}{2} +n

2n^3+6n^2+6n=6S+3n^2+3n+2n

6S=2n^3+3n^2+n

6S=2n^2(n+1)+n(n+1)

6S=(n+1)(2n^2+n)

6S=n(n+1)(2n+1)

S=\frac{n(n+1)(2n+1)}{6}

Hence, the formula is \frac{n(n+1)(2n+1)}{6}

Learn more about Series here:

brainly.com/question/24643676

#SPJ1

3 0
2 years ago
Lines
GuDViN [60]

Answer: it is b

Step-by-step explanation:

i took the test boys

5 0
3 years ago
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