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Lina20 [59]
3 years ago
8

Quick need answer!!!!!!

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer:

75.5°

Step-by-step explanation:

Cos(A) = 2/8 = 0.25

A = 75.52248781

hammer [34]3 years ago
3 0

Answer:

A = 75.5

Step-by-step explanation:

\cos(a)  =  \frac{2}{8}  \\  \cos(a)  =  \frac{1}{4}   \\ a = 75.5

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13. Oscar's dog house is shaped like a tent. The slanted sides are both 5 feet
VashaNatasha [74]

Answer:

The height of the dog house = 4 feet.

Step-by-step explanation:

Given:

The shape of the dog house is like a tent.

The slant heights of the house is 5 feet.

The bottom of the house is 6 feet across.

To find the height of the dog house at its tallest point.

Solution:

On drawing the figure of the dog house in the shape of a tent, we find out that the tallest point would be at the midpoint of the bottom of the house.

Thus, we ave a right triangle, of which one leg = \frac{6\ ft}{2}=3\ ft and hypotenuse = 5\ ft

<em>Applying Pythagorean theorem to find the measure of the other leg which is the height of the house.</em>

Hypotenuse^2=Leg1^2+Leg2^2

Plugging in values.

5^2=3^2+Leg2^2

25=9+Leg2^2

Subtracting both sides by 9.

25-9=9-9+Leg2^2

16=Leg2^2

Taking square root both sides.

\sqrt{16}=\sqrt{Leg2^2}

4=Leg2

Thus, the height of the dog house = 4 feet.

6 0
4 years ago
Kyilah bought 41.19 grams of chili and 19.415 grams of sugar. Did Kyilah buy more chili or sugar?
Sauron [17]

Answer:

Chili I think, I don't know for certain

Step-by-step explanation:

7 0
2 years ago
What is the area of the trapezoid? 34 square units 42 square units 84 square units 118 square units.
Anvisha [2.4K]

Answer:

42 square units

Step-by-step explanation:

For a better understanding, I add an EFGH Rectangle.

The area of EFGH Rectangle = p x l

The area of EFGH Rectangle = 10 x 8

The area of EFGH Rectangle = 80cm²

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x a x t

The area of BHA Triangle = 1/2 x 6 x 4

The area of BHA Triangle = 2 x 6

The area of BHA Triangle = 12cm²

The area of AGD Triangle = 1/2 x a x t

The area of AGD Triangle = 1/2 x 4 x 2

The area of AGD Triangle = 4cm²

The area of CFD Triangle = 1/2 x a x t

The area of CFD Triangle = 1/2 x 2 x 6

The area of CFD Triangle = 6cm²

The area of BEC Triangle = 1/2 x a x t

The area of BEC Triangle = 1/2 x 8 x 4

The area of BEC Triangle = 4 x 4

The area of BEC Triangle = 16cm²

The area of the trapezoid = EFGH Rectangle - (BHA Triangle + AGD Triangle + CFD Triangle + BEC Triangle)

The area of the trapezoid = 80 - (12 + 4 + 6 + 16)

The area of the trapezoid = 80 - 38

The area of the trapezoid = 42cm²

5 0
2 years ago
Read 2 more answers
Answer and explain how pls
NISA [10]

Answer:

I think itsa 4 x 155 = 620

Step-by-step explanation:

3 0
3 years ago
Can you help me solve and describe the steps used to find x for the equation 2(x + 4) – 10 = 12
Anettt [7]

Hi there!


To solve, let's rewrite this equation.


2 (x + 4) - 10 = 12


Step 1) Simplify both sides of the equation.


(2) (x) + (2) (4) + - 10 = 12 2x + 8 + - 10 = 12 (Distribute)


(2x) + (8 + - 10) = 12 (Combine Like Terms)


2x + - 2 = 12 2x - 2 = 12


Step 2) Add 2 to both sides.


2x - 2 + 2 = 12 + 2 2x = 14


Step 3) Divide both sides by 2.


\frac{2x}{2} =  \frac{14}{2}


x = 7


Final Answer -


x = 7


Hope this helps!

Message me if you need anything else, I'd be happy to help you! :D


3 0
3 years ago
Read 2 more answers
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