Question

-16t^2+64t=0 t=? can someone help me what t equals!!

Answer 1

Answer:

see the explanation

Step-by-step explanation:

we have

$-16t^2+64t=0$

Solve for t

Factor -16t

$-16t(t-4)=0$ ----> quadratic equation in factored form

therefore

The solutions are

$t=0, t=4$

Answer 2

For this case we must solve the following equation:

$-16t ^ 2 + 64t = 0$

Taking common factor $16t$we have:

$16t (-t + 4) = 0$

Thus, it is observed that equality is fulfilled when:

$t = 0\\t = 4$

Thus, the solution of the equation is given by:

$t_ {1} = 0\\t_{2} = 4$

Answer:

$t_ {1} = 0\\t_{2} = 4$