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11Alexandr11 [23.1K]
3 years ago
12

a Special Olympics event has 14 more boys than girls competing the total number of participants is 1000 how many boys competed a

nd how many girls competed
Mathematics
2 answers:
prisoha [69]3 years ago
5 0

Answer:

493 girls and 507 boys competed.

Step-by-step explanation:

Let x represent number of girls.

We have been given that a Special Olympics event has 14 more boys than girls competing. So the number of boys would be x+14.

We are also told that the total number of participants is 1000. We can represent this information in an equation as:

x+x+14=1000

2x+14=1000

2x+14-14=1000-14

2x=986

\frac{2x}{2}=\frac{986}{2}

x=493

Therefore, 493 girls competed in the Olympics.

Number of boys: x+14\Rightarrow 493+14=507

Therefore, 507 boys competed in the Olympics.

kotykmax [81]3 years ago
3 0
Girls=x
boys=x+14
x+x+14=1000
2x+14=1000
2x=1000-14
2x=986
x=493
girls=x=493
boys=x+14=493+14=507
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