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Ainat [17]
3 years ago
9

A.) 10.9 B.) 8.6 C.) 7.3

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

Option (c) 7.3

Step-by-step explanation:

Since is forms a right angled traingle,

a= 3+4= 7

b = 4-2= 2

c = AB

Pythagorean theorem:

a^2+b^2 = c^2

So since we know a and B but the hypotenuse (c) is missing

7^2 + 2^2 = c^2

c^2 = 49+4

= 53

c = √53

= 7.28 rounded off to 7.3

So the length of hypotenuse or c is 7.3 units

Therefore, the length is 7.3

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Answer:

I'm not sure if you mean the type of triangle or the other number but I'm pretty sure it's an equilateral triangle and the the number is 8.

Step-by-step explanation:

6 0
3 years ago
The floor in Lila's bedroom is 30 square yards. Calculate the area in square feet
love history [14]
1 sq yrd = 9 sq. ft 
so 30 sq. yards times 9 = 270 square feet

-"270 square feet"-
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3 years ago
Read 2 more answers
For the data set 6, 5, 10, 11, 13, the mean, X, is 9. What is the standard<br> deviation?
Ket [755]

Answer:

standard deviation = 3.0331

Step-by-step explanation:

You can solve for this two different ways.

If you have a TI-84 calculator or something similar, type all the data into list 1. Then click the stat button, then the calc button, then 1-vars stats. This will give you mean, standard deviation, median, mode, etc.

If you are solving by hand, find the different between each data point and the mean. Square these numbers and find the average. Then take the square root of that.

3^2 + 4^2 + 1^2 + 2^2 + 4^2 = 46

46/5 = 9.2

square root of 9.2 = 3.0331

Hope this is helpful!!!!!!!!!!! :)

4 0
3 years ago
Which of the following points would be a solution to this system of linear inequalities? ​
pychu [463]

Let's plug in both x and y values in the equation and check if the inequality is true...

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

(4,1) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 4 and y as 1

1 \leqslant 4 + 1 \\ 1 <  -  \frac{4}{2}  - 1

0  \leqslant  4 + 1 \\ 1 <  - 2 - 1

0 \leqslant 5 \\ 1 <  - 3

  • <em>This is not a solution because both are not true, Only one equation is giving true as answer which is not correct!~</em>

\purple{ \rule{300pt}{3pt}}

(0, - 3) \\ y \leqslant x + 1 \\ y <  -  \frac{x}{2}  - 1

Substitute x as 0 and y as -3

- 3 \leqslant 0 + 1 \\  - 3 <  -  \frac{0}{2}  - 1

- 3 \leqslant 1 \\  - 3 <  - 0 - 1

- 3 \leqslant 1 \\  - 3 <  - 1

  • <em>This is a solution because both are true, </em><em>Both the </em><em>equations</em><em> </em><em>are</em><em> </em><em>true</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>the</em><em> </em><em>ordered</em><em> </em><em>pair</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>solution</em><em>!</em><em>~</em>

<u>Thus</u><u>,</u><u> </u><u>Option</u><u> </u><u>B</u><u> </u><u>(</u><u>0</u><u>,</u><u>-</u><u>3</u><u>)</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>correct</u><u> </u><u>choice</u><u>.</u><u>.</u><u>.</u><u>.</u>

6 0
3 years ago
Is this aa theorem or sas theorem
sergey [27]
I believe this is SAS because the angles are not the same so it cannot be angle angle it has to be SAS
8 0
3 years ago
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