Group 'em together
a
b
−
a
+
1
−
b
a
b
−
a
=
a
(
b
−
1
)
Notice that there will be a 1 as without it it'll simply be ab
1
−
b
=
1
(
1
−
b
)
Notice that it doesn't match with the upper one... so we'll change the signs
1
(
1
−
b
)
=
−
1
(
b−
1
)
(try to multiply them now!!
Jot them down in one expression
a
(
b
−
1
)
−
1
(
b
−
1
)
You get!!!!!!
(
a
−
1
)
(
b
−
1
)
Explanation:
We usually use graphs to solve two linear equations in two unknowns.
The basic idea is that a graph of an equation is the pictorial representation of all of the points that satisfy the equation. So, where the graph of one equation crosses the graph of another, the point where they cross will satisfy both equations.
Finding a solution means finding values of the variables that satisfy all of the equations. Hence, the point of intersection is the solution of the equations.
__
To solve linear equations by graphing, graph each of the equations. Then find the coordinates of the point where the lines intersect. Those coordinates are the solution to the equations.
If the solution is not at a grid point on the graph, determining its exact value may not be easy. This can often be aided by a graphing calculator, which can often tell you the point of intersection to calculator accuracy.
__
If the lines don't intersect, there are no solutions. If they are the same line (intersect everywhere), then there are an infinite number of solutions.
Find ever origin and then multiplying by the <span>scale factor of 2 and i promise you will get your answer</span>
C and D are the same, so its between A and B, which concludes your answer should be B
In simplifying inequalities, there are a few things that you have to remember. Here are some:
<span>Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own.
But these things will change direction of the inequality:<span>Don't multiply or divide by a variable (unless you know it is always positive or always negative)
We simplify as follows:
2i/2<6u/2
i<3u</span></span>
