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Papessa [141]
3 years ago
8

If a triangle has an area of 108 mm2 and the base of the triangle is 18 mm, what is the height of the triangle? PLEASE HELP ME

Mathematics
2 answers:
Aloiza [94]3 years ago
5 0

Answer:

height = 12 \:  \: mm

Step-by-step explanation:

area =  \frac{1}{2}  \times height \times base \\ 108 =  \frac{1}{2}  \times h \times 18 \\ 108 =  \frac{18h}{2}  \\ 108 = 9h \\  \frac{108}{9} =  \frac{9h}{9}  \\ h = 12

hope this helps

brainliest appreciated

good luck! have a nice day!

OleMash [197]3 years ago
4 0

Answer:12

Step-by-step explanation:

Area=1/2base xheight

(108×2)÷18

12

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Sedbober [7]

5 : Dividend

6 : Divisor

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<u>9 : 5550 Divided by 925 : 6</u>

<em>Hope this helps</em>

3 0
3 years ago
Help please.......... I need answers
Vikentia [17]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
How much will Chris’s investment account be worth in five years if he invests $5,000 with 2.8% interest?
vovikov84 [41]

Answer:

\$5,700

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=5\ years\\ P=\$5,000\\r=0.028

substitute in the formula above

A=\$5,000(1+0.028*5)

A=\$5,000(1.14)=\$5,700

6 0
3 years ago
What is the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12)?
ki77a [65]

The general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

<h3>What is the vertex form of a quadratic equation?</h3>

Vertex form of the quadratic equation is used to find the coordinate of vertex points at which it crosses its symmetry.

The standard equation of the vertex form of quadratic is given as,

y=a(x-h)^2+k

Here, (h, k) is the vertex point.

The vertex of quadratic at (2, 3) and passing through the point (5, 12). Put the value of vertex point in the above equation,

y=a(x-2)^2+3

As the quadratic passes through the point (5, 12). Thus, put the value of this point,

12=a(5-2)^2+3\\12-3=a(3)^2\\9=a\times9\\a=\dfrac{9}{9}\\a=1

Put the value of <em>a</em> in the above expression,

y=1(x-2)^2+3\\y=(x-2)^2+3\\y=x^2-4x+4+3\\y=x^2-4x+7

Thus, the general form of the quadratic with vertex at (2, 3) and passing through the point (5, 12) is x²-4x+7.

Learn more about the vertex form here;

brainly.com/question/17987697

#SPJ1

4 0
3 years ago
What is the value of x?
sineoko [7]
90 = 49 + x
90° - 49° = x
41 = x

I decrease it with 90 because the corner is facing. I hope the answer is right...
6 0
3 years ago
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