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Brilliant_brown [7]
3 years ago
14

Derivative of square root of (lnx)

Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0
Use the chain rule

y = √[ln(x)]=> y' = [1/2√(lnx)]*[ln(x)]' = [1/2√(lnx) ] * 1/x = 1 / [2x(√lnx)]
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