The Reactance of a Capacitor is t<u>he resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. </u>This is measured in ohms (Ω) and its formula is:
(1)
Where:
is the Reactance in ohms (Ω)
is the frequency of the alternating current in Hertz (
)
is the Capacitance of the Capacitor in Farad (
)
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note 
Well, with the given data we have to solve (1):
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
(2x + 3) + (x+1) + (3x-10) = 180
6x - 6 = 180
6x = 186
x= 31
Answer:
2x³+5x²+7x+5
Step-by-step explanation:
(x² + 4x² + x³ + x) + (x³ + x + 5x + 5)
(5x²+x³+x)+(x³+6x+5)
2x³+5x²+7x+5
60 is the answer I just can't do long division on here
Your answer to the question would be g(x)=4x-3
