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KonstantinChe [14]
3 years ago
5

Please help asap 25 pts

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

B, shaded region below a dashed boundary line

Step-by-step explanation:


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Max has just won some money on a game show! He has the option to take a lump sum payment of $500,000 now or get paid an annuity
Fofino [41]

Answer:

The second option annually

Step-by-step explanation:

(4,900×12)×10 the multiply by 2.9%. Take that number and add on every 10 years

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Mr. Johnson has a garden in the shape of a kite with a length of 5 feet and a width of 4 feet. A bag of topsoil covers 10 square
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3 years ago
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Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
Choose all true statements.
serious [3.7K]

Answer:

Some rational numbers are natural numbers  

All whole numbers are integers  

Some integers are natural numbers.

Step-by-step explanation:


3 0
3 years ago
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Real easy math i just dont wanna do my hw.​
ahrayia [7]

Answer:

6x^2 (3x^2 - 2)

Step-by-step explanation:

18x^4 - 12x^2

6x^2 (3x^2 - 2)

6 0
3 years ago
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