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Brrunno [24]
3 years ago
6

The management option that can provide on-site infrastructure access when the network is down or complete remote access in cases

of connectivity failures on the network, such as via a cellular signal, is known as?
Business
1 answer:
muminat3 years ago
6 0

Answer:

It is known as out-of-band management

Explanation:

Out-of-band management is a device and system management technique that involves an alternative and efficient connection to the system which is separate from the main network that the system runs on allowing an administrator to establish a system of trust boundaries since there would only be a single entry point for the management interface.

Device management through out-of-band management is very secure and safe because it does not allow any unauthorized user to be able to access the network channel because there is no connection from the regular network channel that is available for everyone.

This channel management interface is very efficient and a very powerful management tool because it is always available even when network is down or device is turned off or not accessible through the operating system making it easy to be remotely managed.

An example configuration for out-of-band management is the blade systems with dedicated management modules often offering a dedicated OOB Ethernet port

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A string or rope will break apart if it is placed under too much tensile stress. Thicker ropes can withstand more tension withou
kifflom [539]

Answer:

a. radius = 0.0006m = 0.6mm and length =0.393m = 393mm

b. frequency =377.86Hz

Explanation:

Given:

mass of steel= 4g = 0.004kg

density of steel = 7890kg/m3

tensile stress of steel 7.0x10⁸

tension load =900N

from the density, we will calculate for the Volume of the steel string

density = mass/volume

volume = mass/density = 0.004/7890 = 5.07 x 10⁻⁷ m³

from the tensile stress will can get the maximum base Area of the string ,

tensile stress = load/area =

7x10⁸ = 900/A

A = 900/7x10⁸ = 1.29x10⁻⁶ m²

Area = πr²

area/pi = 4.105x10-7

radius = 0.0006m = 0.6mm

volume = Area x length

length = vol/area =(5.07 x 10⁻⁷ m³)/1.29x10⁻⁶ m² = 0.393m

b. the highest possible frequency is given by:

F = \frac{\sqrt{\frac{T}{m/L} }}{2L}

where T= tension, m=mass, L=length

F = \frac{\sqrt{\frac{900}{0.004kg/0.393m} }}{2*0.393m}

= 297.04/0.786

frequency =377.86Hz

4 0
3 years ago
For each of the following, compute the present value: (Do not round intermediate calculations and round your answer to 2 decimal
timurjin [86]

Answer:

Present value = FV / (1 + r)^t

1. PV = $19,415 / (1 + 0.07)^15

PV = $19,415 / (1.07)^15

PV = $19,415 / 2.759031

PV = $7,036.89

2. PV = $47,382 / (1 + 0.11)^8

PV = $47,382 / (1.11)^8

PV = $47,382 / 2.3045378

PV = $20,560.31

3. PV = $312,176 / (1 + 0.10)^13

PV = $312,176 / (1.10)^13

PV = $312,176 / 3.4522712

PV = $90,426.27

4. PV = $629,381 / (1 + 0.13)^25

PV = $629,381 / (1.13)^25

PV = $629,381 / 21.230542

PV = $29,645.07

5 0
3 years ago
Software Riverside Company issued long-term debt of 410 paid dividends of 20 and issued capital stock of 100. Cash flow from fin
Mazyrski [523]

Answer:

Cash flow from from financing activities = $490

Explanation:

<em>The cash flow from financing activities includes that entails any or a combination of the following; issuance and redemption of stocks , issuance and redemption of debts and payment of interest and/or dividend, and receipt of dividend and or interest.  </em>

Cash flow                                    $

issue of long term debt           410

Cash dividend paid                  (20)

Capital stock issued                  <u>100 </u>

Net cash from financing activ.  <u>490</u>

Cash flow from from financing activities = $490

8 0
3 years ago
Various financial data for Year 1 and Year 2 follow. Calculate the total productivity measure and the partial productivity measu
Ber [7]

Answer:

See below

Explanation:

With regards to the above, the formula for total productivity measure is

= Output Sales( Total output) / Total Input

Total productivity measurement for Last year.

Output sales = $200,000

Total input = Input labor + Raw materials + Energy + Capital + others

= $30,000 + $35,000 + $5,000 + $50,000 + $2,000

= $122,000

Therefore, total productivity measure

= $200,000/$122,000

= 1.64

Total productivity measurement for this year

Output sales= $220,000

Total input = Input labor + raw materials + energy + capital + others

= $40,000 + $45,000 + $6,000 + $50,000 + $3,000

= $144,000

Therefore, total productivity measure

= $220,000/$144,000

= 1.53

Partial productivity for last year

Output sales = $200,000

Input = Input labor + raw materials + capital

= $30,000 + $35,000 + $50,000

= $115,000

Partial productivity measure = $200,000/$115,000

= 1.74

Partial productivity measure for this year

Output sales = $220,000

Input = Input labor + raw materials + capital

= $40,000 + $45,000 + $50,000

= $135,000

Therefore, partial productivity measurement for last year

= $220,000/$135,000

= 1.63

The above measures indicates that there is a reduction in total productivity measures from last year to this year. Same applies to partial productivity measures for both years.

8 0
3 years ago
To get an idea of whether you should continue to run a search network campaign on search partner sites, you can:
ziro4ka [17]
You can separate or group the campaign's data by network and evaluate its performance on search partner sites
5 0
3 years ago
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