Please help been working on for 2 hours

Solve the inequality 5y+4 ≤ 22-y and graph the solution set on a number line. Please explain how to do it!

gtnhenbr [62]

Answer:

y≤3

Step-by-step explanation:

5y+4≤22−y

Step 1: Simplify both sides of the inequality.

5y+4≤−y+22

Step 2: Add y to both sides.

5y+4+y≤−y+22+y

6y+4≤22

Step 3: Subtract 4 from both sides.

6y+4−4≤22−4

6y≤18

Step 4: Divide both sides by 6.

6y/6≤18/6

y≤3

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2 years ago

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You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$