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2 years ago

12

1) The center of a circle is at (-10,6) and it has a radius of 4. What is the equation of the circle?

1 answer:

krok68 [10]2 years ago

8 0

1. (x - h)² + (y - k)² = r²
(x - (-10)) + (y - 6)² = 4²
(x + 10)² + (y - 6)² = 16
The equation of the circle is (x + 10)² + (y - 6)² = 16.

2. The answer is A.

3. The equation of the parabola is y = ⁻⁵/₃₆x² - 1²/₃x - 2.

4. I don't know the answer to the problem.

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Read 2 more answers

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a sprin

vlada-n [284]

Answer:

The work done is 202.50Nm

Step-by-step explanation:

Given

$F =450N$

$x_1 = 30cm$

$x_2 = 60cm$

Required

The work done

First, we calculate the spring constant (k)

$F = kx_1$

$450N = k *30cm$

$k = \frac{450N}{30cm}$

$k =15N/cm$

So:

$F = kx_1$

$F(x) = 15x$

The work done using Hooke's law is:

$W =\int\limits^a_b {F(x)} \, dx$

This gives:

$W =\int\limits^{60}_{30} {15x} \, dx$

Rewrite as:

$W =15\int\limits^{60}_{30} {x} \, dx$

Integrate

$W =15 \frac{x^2}{2}|\limits^{60}_{30}$

This gives:

$W =15 *\frac{60^2 - 30^2}{2}$

$W =15 *\frac{2700}{2}$

$W =15 *1350$

$W =20250N-cm$

Convert to Nm

$W =\frac{20250Nm}{100}$

$W =202.50Nm$

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