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Lelu [443]
4 years ago
12

Given: f(x)=x^(2)-3 and g(x)=x+1 the composite function g*f is

Mathematics
2 answers:
Ivenika [448]3 years ago
8 0

Answer:

<h2>x³ + x² - 3x - 3</h2>

Step-by-step explanation:

I'm assuming g*f means g times f,  so you want to multiply the two functions together.  

(x² - 3)(x + 1)                 Since the product is 2 binomials, use FOIL

                      =  x²(x) + x²(1) - 3(x) - 3(1)

which simplifies to

<h2>x³ + x² - 3x - 3</h2>
qaws [65]3 years ago
4 0

Answer: x³ + x² - 3x - 3

Step-by-step explanation:

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3 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),[0, π/2].
castortr0y [4]

Answer:

The absolute maximum is \frac{3\sqrt 3}2 and the absolute minimum value is 0.

Step-by-step explanation:

Differentiate of f both sides w.r.t.  t,

f(t)=2 \cos t+\sin 2t

\Rightarrow f'(t)=-2\sin t+2\cos 2t

Now take f'(t)=0

\Rightarrow -2\sin t+2\cos 2t=0

\Rightarrow 2\cos 2t=2\sin t

\Rightarrow \cos 2t=\sin t

\Rightarrow 1-2\sin ^2t =\sin t  \quad \quad  [\because \cos 2t = 1-2\sin ^2t]

\Rightarrow 2\sin ^2t+\sin t-1=0

\Rightarrow 2\sin ^2t+2\sin t-\sin t-1=0

\Rightarrow 2\sin t(\sin t+1)-1(\sin t+1)=0

\Rightarrow (\sin t+1)(2\sin t-1)=0

\Rightarrow \sin t+1=0  \;\text{and}\; 2\sin t-1=0

\Rightarrow \sin t =-1  \;\text{and}\;   \sin t =\frac 12

In the interval 0\leq t\leq \frac {\pi}2, the answer to this problem is \frac {\pi}6

Now find the second derivative of f(t) w.r.t.   t,

f''(t)=-2\cos t-4\sin 2t

\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3

Thus, f(t) is maximum at t=\frac {\pi}6 and minimum at t=0

\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0

Hence, the absolute maximum is \frac{3\sqrt 3}2 and the absolute minimum value is 0.

7 0
3 years ago
Two parrelel chords 16 centimeters and 30 centimeters long are 23 centimeters apart. find the length of the radius of the circle
BARSIC [14]
<span>r^2 = 529 - 46x + x^2 + 64
r^2 = x^2 - 46x + 593
replace r^2 with (x^2+ 225)
x^2 + 225 = x^2 - 46x + 593
x^2 - x^2 + 46x = 593 - 225
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x = 368/46
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r^2 = 289
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7 0
3 years ago
In what direction and by how many units is the graph of f(x) = −3 cos(2x − π) + 2 vertically and horizontally shifted
MakcuM [25]

Answer:

Vertical shift is 2 units top and horizontal shift is \frac{\pi }{2} units to the right

Step-by-step explanation:

Consider the function f(x) = a cos(bx + c) + d.

In this graph, the horizontal shift is -c/b and the vertical shift is d.

Let's compare our graph, f(x) = -3 cos(2x - π) + 2 with this graph.

Here, a = -3, b = 2, c = -π and d = 2.

So, vertical shift = d = 2 units top and

horizontal shift = -\frac{c}{b} =-\frac{-\pi }{2} =\frac{\pi}{2} units to the right.


8 0
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Answer:

The bus can travel 3 miles with 1 gallon of gas

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
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