Well, in slope-intercept form, the equation will be y = x + 4. In standard form, the equation will be x - y = -4.
Answer:
150.9 cubic inches
Step-by-step explanation:
volume of he gas = volume of a cone x 3/4
Volume of a cone 1/3(nr^2h)
n = 22/7
r = radius
h = height
the diameter is the straight line that passes through the centre of a circle and touches the two edges of the circle.
A radius is half of the diameter
8/2 = 4 inches
1/3 (22/7 x 4^2 x 12) = 201.142857 in^3
volume of the gas = 3/4 x 201.142857 in^3 = 150.9 in^3
the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero
Let c > 0. Then split the integral at t = c to write
By the FTC, the derivative is
![\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bdf%7D%7Bdx%7D%20%3D%20%5Cleft%28%5Cfrac1x%20%2B%20%5Csin%5Cleft%28%5Cfrac1x%5Cright%29%5Cright%29%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Cfrac1x%5Cright%5D%20-%20%28%5Cln%28x%29%20%2B%20%5Csin%28%5Cln%28x%29%29%29%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Cln%28x%29%5Cright%5D%20%5C%5C%5C%5C%20%3D%20-%5Cfrac1%7Bx%5E2%7D%20%5Cleft%28%5Cfrac1x%20%2B%20%5Csin%5Cleft%28%5Cfrac1x%5Cright%29%5Cright%29%20-%20%5Cfrac1x%20%28%5Cln%28x%29%20%2B%20%5Csin%28%5Cln%28x%29%29%29%20%5C%5C%5C%5C%20%3D%20-%5Cfrac1%7Bx%5E3%7D%20-%20%5Cfrac%7B%5Csin%5Cleft%28%5Cfrac1x%5Cright%29%7D%7Bx%5E2%7D%20-%20%5Cfrac%7B%5Cln%28x%29%7Dx%20-%20%5Cfrac%7B%5Csin%28%5Cln%28x%29%29%7Dx%20%5C%5C%5C%5C%20%3D%20-%5Cfrac%7B1%20%2B%20x%5Csin%5Cleft%28%5Cfrac1x%5Cright%29%20%2B%20x%5E2%5Cln%28x%29%20%2B%20x%5E2%20%5Csin%28%5Cln%28x%29%29%7D%7Bx%5E3%7D)
Answer: 3p² + q² - 5pq - 10 < 0
<u>Step-by-step explanation:</u>
p² - q² + 2pq < -2p² - 2q² + 7pq + 10
since you didn't specify what to solve for, move everything from the right side to the left side of the inequality symbol using inverse operations.
(p² + 2p²) + (- q² + 2q²) + (2pq - 7pq) + (- 10) < 0
3p² + q² + -5pq + -10 < 0
3p² + q² - 5pq - 10 < 0
Answer:
C
Step-by-step explanation:
That means that for x=3 the y has a value of 1.
