The mode of the numbers is 5, which means that 5 should be the most common card (highest frequency). Therefore the cards should have at least one more 5 among them.

Considering that 5 is one of the hidden cards and x is the other,

• Using the equation for the mean:

$mean = \frac{sum \space\ \space\ of \space\ \space\ numbers}{number \space\ \space\ of \space\ \space\ numbers}$

$6 = \frac{4+5+ 9 + 5 + x}{5}$

⇒ $30=23 + x$

⇒ $x = 7$

This means 5 and 7 are the hidden cards.

3 0

2 years ago

1/3x(-6+27y-51z)simplify

Naya [18.7K]

Final result :

9y - 17z - 2
Step by step solution :

Step 1 :

1
Simplify —
3
Equation at the end of step 1 :

1
— • (27y - 51z - 6)
3
Step 2 :

Pulling out like terms :

3.1 Pull out like factors :

27y - 51z - 6 = 3 • (9y - 17z - 2)

Final result :

9y - 17z - 2

8 0

3 years ago

Read 2 more answers

How do you solve this equation 2/3b=-12

Airida [17]

2/3b = 12

First you have to get rid of 2/3, so you multiply both sides by its reciprical:
(3/2) 2/3b = 12 (3/2) -->b = 36/2 --> b = 18

5 0

3 years ago

Hey guys- need help here. Topic- exponents.

evablogger [386]

Your answer is m= -12

5 0

2 years ago