X = 3y3x - 5y = 12 substitution
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Using the normal distribution, it is found that approximately 40% of the scores are greater than 413.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, we have that the mean and the standard deviation of the scores are given by:
Approximately 40% of the scores are greater than the 60th percentile, which is <u>X when Z = 0.253</u>.
Then:
X - 400 = 50(0.253)
X = 412.65.
Rounding up, approximately 40% of the scores are greater than 413.
More can be learned about the normal distribution at brainly.com/question/24663213
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