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zepelin [54]
3 years ago
14

Draw a quardrilateral that is not a rectangle describe your shape and explain why it is not a rectangle

Mathematics
1 answer:
arsen [322]3 years ago
5 0
I would draw a trapezoid.

Trapezoids are quadrilaterals with one pair of parallel lines, not two. A rectangle has two pairs of parallel lines and is congruent. Therefore, it is not a rectangle.

Hope this helps... mark as Brainliest plz
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Answer:

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Step-by-step explanation:

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Need help anyone who can help plz
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Answer:

A) x=40°

B) They have the same lengths.

Step-by-step explanation:

Since it is an isosceles triangle, both sides are the same. So if you add up all the angles of any triangle, it should always add up to 180°. There is a 50° angle and a right angle (90°) so you subtract 50 and 90 from 180 (180-50-90) and you get 40. X has to be 40° :)

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Find the equation of the parabola that passes through
valentinak56 [21]

so we have the points of (0,-7),(7,-14),(-3,-19), let's plug those in the y = ax² + bx + c form, since we have three points, we'll plug each one once, thus a system of three variables, and then we'll solve it by substitution.

\bf \begin{array}{cccllll} \stackrel{\textit{point (0,-7)}}{-7=a(0)^2+b(0)+c}& \stackrel{point (7,-14)}{-14=a(7)^2+b(7)+c}& \stackrel{point (-3,-19)}{-19=a(-3)^2+b(-3)+c}\\\\ -7=c&-14=49a+7b+c&-19=9a-3b+c \end{array}

well, from the 1st  equation, we know what "c" is already, so let's just plug that in the 2nd equation and solve for "b".

\bf -14=49a+7b-7\implies -7=49a+7b\implies -7-49a=7b \\\\\\ \cfrac{-7-49a}{7}=b\implies \cfrac{-7}{7}-\cfrac{49a}{7}=b\implies -1-7a=b

well, now let's plug that "b" into our 3rd equation and solve for "a".

\bf -19=9a-3b-7\implies -12=9a-3b\implies -12=9a-3(-1-7a) \\\\\\ -12=9a+3+21a\implies -15=9a+21a\implies -15=30a \\\\\\ -\cfrac{15}{30}=a\implies \blacktriangleright -\cfrac{1}{2}=a \blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{and since we know that}}{-1-7a=b}\implies -1-7\left( -\cfrac{1}{2} \right)=b\implies -1+\cfrac{7}{2}=b\implies \blacktriangleright \cfrac{5}{2}=b \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-\cfrac{1}{2}x^2+\cfrac{5}{2}x-7~\hfill

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3 years ago
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vovangra [49]

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Tom [10]
The acute angles of a right triangle are complementary, so
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Then the value of α is ...
  α = 5*24/3 +20 = 60
7 0
3 years ago
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