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3 years ago

Janine wants a necklace 21 beads long how many blue beads and how many black beads

Mathematics

1 answer:

Kipish [7]3 years ago

3 0

She needs 11 blue beads and 11 black beads

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8(3a+5)???? please help!!!!!! ASAP!!!!

r-ruslan [8.4K]

I'm assuming your teacher wants you to distribute. If so, then you multiply the outer term 8 by each term inside (3a and 5). After that you add.

8 times 3a = 24a

8 times 5 = 40

So 8(3a+5) becomes 24a+40

We do not combine 24a and 40 as they are not like terms. So we leave 24a+40 as it is.

3 0

3 years ago

Read 2 more answers

a certain state the license plate has two digits, then two letters, and then two digits. How many different license plates are p

xxTIMURxx [149]

Step-by-step explanation:

Choosing 4 digits out of 10 = 10C4 = 210.

Arranging the 4 digits in 4 places = 4!

Total number of ways to arrange digits

= 210 * 4! = 5040.

Choosing 2 letters out of 26 = 26C2 = 325

Arranging the 2 letters in 2 places = 2!

Total number of ways to arrange letters

= 325 * 2! = 650.

Total number of possible license plates

= 5040 * 650 = 3,276,000.

7 0

3 years ago

Read 2 more answers

What is the distance between the points (-1, 8) and (5, 8) in the coordinate plane?

natta225 [31]

The answer should be 6 units. -1 > 0 > 1 > 2 > 3 > 4 > 5 : 6 units

8 0

3 years ago

quadrilateral paid is a rectangle whose diagonals have the endpoints p(-3, -2)i(4, -7) and a(4, -2)d(-3, -7). find the diagonals

julia-pushkina [17]

Answer:

The intersection point of diagonals is (0.5,-4.5).

Step-by-step explanation:

The end points of first diagonal are p(-3, -2) and i(4, -7).

The end points of second diagonal are a(4, -2) and d(-3, -7).

If a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

The equation of first diagonal is

$y-(-2)=\frac{-7-(-2)}{4-(-3)}(x-(-3))$

$y+2=\frac{-5}{7}(x+3)$

$7y+14=-5(x+3)$

$7y+14=-5x-15$

$5x+7y=-29$ .... (1)

The equation of second diagonal is

$y-(-2)=\frac{-7-(-2)}{-3-4}(x-4)$

$y+2=\frac{-5}{-7}(x-4)$

$7y+14=5(x-4)$

$7y+14=5x-20$

$5x-7y=34$ .... (2)

Add equation (1) and (2),

$10x=5$

$x=0.5$

Put this value in (1).

$5(0.5)+7y=-29$

$y=-4.5$

The intersection point of diagonals is (0.5,-4.5).

3 0

3 years ago

Please help me before it's to late I

gregori [183]

It’s 7.406 , that’s the correct answer

5 0

3 years ago