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GrogVix [38]
3 years ago
14

Find the point P along the directed line segment from point A(-16,-8) to point B(0,-17) that divides the segment in the ratio 7

to 6
Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

Answer: P(-7.38,-12.85)

Steps:

Draw the directed line in a chart, including points A and B.

Look for the x coordinate of P:

the distance |B-A| along the x coord is |0-(-16)|=16

we are looking for a proportion of 7/13 of that:

the x coord of P is 16*7/13 to the right of -16, or -16+8.62= -7.38

Look for  y coordinate of P:

the distance |B-A| along the y coord is |-17-(-8)|=9

we are looking for a proportion of 7/13 of that:

the y coord of P is 9*7/13 down from -8, or -8-4.85= -12.85

so the point P is P(-7.38,12.85)


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The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
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Answer:

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Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

the given function is in the standard form i.e

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\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

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\displaystyle x _{ \rm  min} =  \frac{ - 30}{ - 10}

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\displaystyle x _{ \rm  min} =  3

plug in the value of minimum x to the given function:

\displaystyle f (3)=  - 5 {(3)}^{2}  + 30.3 - 200

simplify square:

\displaystyle f (3)=  - 5 {(9)}^{}  + 30.3 - 200

simplify multiplication:

\displaystyle f (3)=  - 45  + 90- 200

simplify:

\displaystyle f (3)=   - 155

hence,

the minimum value of the function is -155

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