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3 years ago

200 meters in 19.30 seconds

Mathematics

1 answer:

DaniilM [7]3 years ago

4 0

The object's speed was about 10.36 meters/second

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In a game, a contestant had a starting score of one point. He tripled his score every turn for four turns. Write his score after

snow_tiger [21]

4 to the power of 1 i think thats the answer

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Shkiper50 [21]

I am not to sure but I think that it is 111.804 inches^3 I hope I am right if not I am really sorry.

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The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu

rjkz [21]

The balloon has a volume $V$ dependent on its radius $r$ :

$V(r)=\dfrac43\pi r^3$

Differentiating with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}$

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

$10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}$

The surface area of the balloon is

$S(r)=4\pi r^2$

and differentiating gives

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}$

so that at the moment the radius is 3 m, its area is increasing at a rate of

$\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}$

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3 years ago

I want the answer of question 27 with explanation

m_a_m_a [10]

Answer:

6√2

Step-by-step explanation:

√32+√18-1√4

√16×2+√9×2-1√2

4√2+3√2-1√2

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Elan Coil [88]

Answer:

Step-by-step explanation:

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