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Mars2501 [29]
3 years ago
10

If you were to use the substitution method to solve

Mathematics
2 answers:
ella [17]3 years ago
7 0

Answer:

x = 1

Step-by-step explanation:

Given :

6x – y = 1  

4x – 3y = –11

To Find : the new equation after the expression equivalent to y from the first equation is substituted into the second equation.

Solution :

6x – y = 1     ---a

4x – 3y = –11   ---b

In equation a

y = 6x-1

Now substitute this value of y in equation b

4x – 3(6x-1)= –11

Thus the new equation : 4x-18x+3 = -11

                                         -14x =-14

                                         x=\frac{-14}{-14}

                                             x=1

Put value of x in equation a

6*1– y = 1

6-y=1

5=y

Thus the solution is (1,5)

Nata [24]3 years ago
6 0
The substitution method:
y = 6 x - 1 ( the new equation )
After that:
4 x - 3 ( 6 x - 1 ) = -11
4 x - 18 x + 3 = - 14
- 14 x = - 14
x = 1,   y = 6 * 1 - 1
y = 5
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Expand the expression?

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Read 2 more answers
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

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3 years ago
What is the radius of the circle using the equation below?
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Answer:

the radius is 5 cubic meters

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