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Black_prince [1.1K]
3 years ago
15

The number sentence 4×7= (4×3) + (4×4) is an example of what property?

Mathematics
1 answer:
velikii [3]3 years ago
7 0

Associative Distributive Transitive Commutative

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Suppose the following number of defects has been found in successive samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6
Brut [27]

Answer:

Given the data in the question;

Samples of size 100: 6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.

a)

For a p chart ( control chart for fraction nonconforming), the center line and upper and lower control limits are;

UCL = p" + 3√[ (p"(1-P")) / n ]

CL = p"

LCL = p" - 3√[ (p"(1-P")) / n ]

here, p" is the average fraction defective

Now, with the 30 samples of size 100

p" =  [∑(6, 7, 3, 9, 6, 9, 4, 14, 3, 5, 6, 9, 6, 10, 9, 2, 8, 4, 8, 10, 10, 8, 7, 7, 7, 6, 14, 18, 13, 6.)] / [ 30 × 100 ]

p" = 234 / 3000

p" = 0.078

so the trial control limits for the fraction-defective control chart are;

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.078 + 3√[ (0.078(1-0.078)) / 100 ]

UCL = 0.078 + ( 3 × 0.026817 )

UCL = 0.078 + 0.080451

UCL = 0.1585

LCL = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.078 - 3√[ (0.078(1-0.078)) / 100 ]

LCL = 0.078 - ( 3 × 0.026817 )

LCL = 0.078 - 0.080451

LCL =  0 ( SET TO ZERO )

Diagram of the Chart uploaded below

b)

from the p chart for a) below, sample 28 violated the first western electric rule,

summary report from Minitab;

TEST 1. One point more than 3.00 standard deviations from the center line.

Test failed at points: 28

Hence, we conclude that the process is out of statistical control

Lets Assume that assignable causes can be found to eliminate out of control points.

Since 28 is out of control, we should eliminate this sample and recalculate the trial control limits for the P chart.

so

p" = 0.0745

UCL = p" + 3√[ (p"(1-P")) / n ]

UCL = 0.0745 + 3√[ (0.0745(1-0.0745)) / 100 ]

UCL = 0.0745 + ( 3 × 0.026258 )

UCL = 0.0745 + 0.078774

UCL = 0.1532

LCL  = p" - 3√[ (p"(1-P")) / n ]

LCL = 0.0745 - 3√[ (0.0745(1-0.0745)) / 100 ]

LCL = 0.0745 - ( 3 × 0.026258 )

LCL = 0.0745 - 0.078774

UCL = 0  ( SET TO ZERO )

The second p chart diagram is upload below;

NOTE; the red circle symbol on 28 denotes that the point is not used in computing the control limits

7 0
2 years ago
What is the smallest value in the stem and leaf plot below?
Alexeev081 [22]
Listing the data from the Stem and Leaves table as raw data we have:

02, 03, 03, 07, 10, 10, 17, 34, 34, 35, 35

Hence the smallest value is 02 = 2

Answer: A
7 0
3 years ago
Emmy throws a doggy toy up in the air. The path of the toy is modeled by the function f(x)=−x^2+4x+5, where x is the number of f
Molodets [167]

Answer:

9feet

Step-by-step explanation:

Given the path of the toy modeled by the function f(x)=−x^2+4x+5, where x is the number of feet the toy is from Emmy and f(x) is the height of the toy.

AT maximum height, the velocity of the toy will be zero. Hence;

df(x)/dx = 0

-2x + 4 = 0

-2x = -4

x = -4/-2

x = 2

Get the maximum height;

Substitute x = 2 into the given function;

f(x)=−x^2+4x+5

f(2)=−2^2+4(2)+5

f(2) = -4+8+5

f(2) = 9feet

Hence the maximum height of the toy is 9feet

4 0
3 years ago
Can I get help please ​
aleksandrvk [35]

Answer:

x > -3.2

Step-by-step explanation:

6 0
3 years ago
I don't know this. Its part of my math homework. 5^9x6/700(3^3)/90+600-9000/5000
Zigmanuir [339]

Answer:

5620.52142857

Step-by-step explanation:

Rounded 5620.52

Your Welcome : )

4 0
3 years ago
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