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3 years ago

10

List the factors of 48 and 54

1 answer:

sergeinik [125]3 years ago

4 0

48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

54: 1, 2, 3, 6, 9, 18, 27, 54

gcf: 6

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We know that
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A population of values has a normal distribution with μ = 247 and σ = 62.2. You intend to draw a random sample of size n = 16. (

nadya68 [22]

Answer:

a) $z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

b) $z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

Step-by-step explanation:

For this case we know that the random variable of interest is normally distributed with the following parameters:

$X \sim N (\mu = 247, \sigma =62.2)$

Part a

We want to find this probability:

$P(X>295.2)$

And we can use the z score formula given by:

$z = \frac{X-\mu}{\sigma}$

Replacing we got:

$z = \frac{295.2-247}{62.2}=0.772$

And using the normal distribution table or excel we got:

$P(Z>0.772) = 1-P(Z$

Part b

We select a random sample of size n = 16 and we try to find this probability:

$P(\bar X >295.2)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{295.5 -247}{\frac{62.2}{\sqrt{16}}}= 3.119$

And we can use the normal standard table or excel in order to find the probability and we got:

$P(z>3.119) =1-P(Z$

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3 years ago