All categories

3 years ago

2. For the graph, find AB to the nearest tenth y 8 А 6 B

Mathematics

1 answer:

zheka24 [161]3 years ago

7 0

Answer:

10.8

Step-by-step explanation:

AB can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

The coordinates of A are when x = -2, y = -2

At B, x = 8, y = -6

Let,

$A(-2, -2) = (x_1, y_1)$

$B(8, -6) = (x_2, y_2)$

Plug the values into the formula.

$AB = \sqrt{(8 - (-2))^2 + (-6 -(-2))^2}$

$AB = \sqrt{(8 + 2)^2 + (-6 + 2)^2}$

$AB = \sqrt{(10)^2 + (-4)^2}$

$AB = \sqrt{100 + 16}$

$AB = \sqrt{116} = 10.8$ nearest tenth

You might be interested in

Factor each.<br><br><br> Please help!

Naddika [18.5K]

Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

$x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0$