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patriot [66]
3 years ago
14

Congruence transformation i need it pls help

Mathematics
1 answer:
juin [17]3 years ago
6 0

Answer:

90 degrees, x axis

Step-by-step explanation:

i mean thats what i think.

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Ughhhhh Its Mondayyyyyyyy soooooo free point question whats 3x+-7=93
Dmitry_Shevchenko [17]

Answer:

3X-7=93,=3x=86=x=28.67

Step-by-step explanation:

4 0
3 years ago
Are the ratios equivalent and how
Hitman42 [59]
 The ratios are equivalent because you multiplied 18:4 by 2&3. And also you divided it by 2. I had the same homework!
4 0
3 years ago
What is the relationship between a 7 and a negative 7
Masteriza [31]

Answer:

They're all the same distance from 0 on the number line.

Step-by-step explanation:

That's a similarity. If you want to know the difference, then it should be that one is greater than 0, and the other is less than 0.

I'm pretty sure that's what you're asking for, right?

8 0
4 years ago
Explain in your own words what congruent triangles have in common with similar triangles? What is the main difference between co
Ket [755]

Answer:

Congruent triangles are the triangles whose shape and size are equal. In other words, the triangles whose corresponding sides and angles are equal, are known as congruent triangles.

Similar triangles are the triangles whose shape is equal but the size may vary.

THANKYOU FOR READING.

7 0
3 years ago
How to find x using trigonometry
I am Lyosha [343]
Soh Cah Toa

Sine of the angle = opposite side over the hypotenuse

sin(42°) = 6.5/h
rearrange, solve for h
h = 6.5/sin(42°)
h = 9.7 cm

For the other triangle, the angle is unknown. I'd split it into two right triangles; down angle x since it is an isosceles it will be bisected into two equivalent triangles.

The hypotenuse we just found is now split in half. 9.7/2 = 4.9 base of the new smaller right triangle.

The new hypotenuse of the smaller triangle is 7.4 cm

Then you have..

sin(x/2) = 4.9/7.4
sin(x/2) = 0.67
use inverse sine function
arcSin(0.67) = x/2
41 = x/2
82° = x

There are many ways to solve this problem. This is just what I thought of first using trig.
3 0
3 years ago
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