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3 years ago

I need help with my math problems

Mathematics

1 answer:

Crazy boy [7]3 years ago

8 0

What kind of help???

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Can I get some help we just started this today

Alja [10]

Answer:

-2

Step-by-step explanation:

The slope of a line tells us how y responds to a change in x. If the slope is 2, it means that for every time x increases by 1, will will go up by 2.

We can calculate slope from a line, or with two given points. I used points (0,4) and (3,-2). Slope is the "Rise/Run."

The Rise: (-2 - 4) = -6

The Run: (3 - 0) = 3

Slope = Rise/Run = (-6/3) = -2

6 0

3 years ago

A 9 pound bag of seed holds 3 pounds less than four smaller bags of seed find the weight of the smaller bag of seed

frosja888 [35]

Answer:

This is a simple question for simple answer

9/3=3

3 seeds

Step-by-step explanation:

4 0

2 years ago

It is 4:12 p.m. Emma's mom will be home from work in 70 minutes, and Emma has gymnastics lessons at 6:00 p.m. How much time will

Mademuasel [1]

We know that her mom will be home in 70 minutes and if its 4:12 then that means that her mom will be home at 5:22 because 70 minutes is 10 minutes more than an hour. If her gymnastics lessons are at 6:00 then she has 38 minutes in-between the time her mom gets home and her gymnastics lesson.

Hope this helped!

8 0

3 years ago

CAN SOMEOBODY ANSWER MY QUESTIONS?? The area of the regular hexagon is 50 in sq. What is the measure of the apothem? 10 in 5 in

Zina [86]

Answer:

25in

Step-by-step explanation:

6 0

3 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$

$d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6$

5 0

2 years ago