<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>9</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
Name three quaderlateral that only sometimes have right angle
Rhombus, trapezoid, and parallelogram
Answer:
60 guests
Step-by-step explanation:
We'll say that the number of guests is n.
We're looking for the n where both of these expressions are equal:
Company A (500 set-up fee, 25 for each guest)
500 + 25 * n
Company B (200 set-up fee, 30 for each guest)
200 + 30 * n
500 + 25n = 200 + 30n
Subtract 200 from both sides.
300 + 25n = 30n
Subtract 25n from both sides.
300 = 5n
We'll reverse the sides.
5n = 300
Divide both sides by 5.
n = 300/5 = 60
Thus, both companies are equal when n is 60, or when there are 60 guests.
Answer:
0.1151 = 11.51% probability of completing the project over 20 days.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Expected completion time of the project = 22 days.
Variance of project completion time = 2.77
This means that 
What is the probability of completing the project over 20 days?
This is the p-value of Z when X = 20, so:



has a p-value of 0.1151.
0.1151 = 11.51% probability of completing the project over 20 days.