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2 years ago

Given the graph below, which of the following statements is true?

Mathematics

1 answer:

Elza [17]2 years ago

7 0

Answer:

Option d is right

Step-by-step explanation:

A function is called one to one if two x will not have same y value.

In other words, in the domain each x is matched with a unique y and if x1 not equals x2 we have the corresponding y1 will not be equal to y2.

In the graph given, we find that the y value say 1 has preimages in both to the right of y axis and to the left of y axis.

Hence this is not one to one.

This is a function because each x has a unique image. If we draw a vertical line in any part of the graph we find that it cuts only one time the graph of f(x)

Hence f is a function but not one to one. A one to one function need not pass through the origin.

Hence we find that of the options given, a,b and c are wrong.

But option d is right.

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7 + 2y^2 Evaluate the expression for Y = 5. Please help me

garik1379 [7]

Answer:

107

Step-by-step explanation:

We first need to input the values of the variables.

7 + 2 x 5^2

7+10^2

7+100 = 107

4 0

2 years ago

7 What is the value of the expression -3x^2 y +4x when x = -4 and y = 2

love history [14]

-3x^2 y +4x
 =-3(-4)^2 (2) + 4(-4)
=-96-16
=-112

7 0

3 years ago

Ajar contains 16 beads. 4 beads are red, 4 are yellow, 5 are green, and 3 are blue.

steposvetlana [31]

Answer:

3/16

Total no.of beads = 16

No.of blue beads = 3

Probability of picking a blue bead = 3/16

Step-by-step explanation:

Hope this helps

can i get braineist pls

3 0

2 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

2 years ago

Lisa had 1750 stamps. Mark had 480 fewer stamps than Lisa. Lisa gave some stamps to Mark. Now Mark has three times as many stamp

FrozenT [24]

L: 1750, M:1750-480=1270
Lisa gave some stamps to Mark so Lisa now has 1750-x and Mark has 1270+x. Mark also has 3 times as many as Lisa now: (1750-x)*3=1270+x
5250-3*x=1270+x
4*x=3980, x=3980/4, x=995
So Lisa gave 995 stamps to Mark.
At first Mark had 1270 stamps. Lisa now has 1750-995=755 stamps.

7 0

2 years ago

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