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Oksi-84 [34.3K]
3 years ago
6

Given the graph below, which of the following statements is true?

Mathematics
1 answer:
Elza [17]3 years ago
7 0

Answer:

Option d is right

Step-by-step explanation:

A function is called one to one if two x will not have same y value.

In other words, in the domain each x is matched with a unique y and if x1 not equals x2 we have the corresponding y1 will not be equal to y2.

In the graph given, we find that the y value say 1 has preimages in both to the right of y axis and to the left of y axis.

Hence this is not one to one.

This is a function because each x has a unique image. If we draw a vertical line in any part of the graph we find that it  cuts only one time the graph of f(x)

Hence f is a function but not one to one.  A one to one function need not pass through the origin.

Hence we find that of the options given, a,b and c are wrong.

But option d is right.

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Which graph shows the solution to the system of linear inequalities? y ≥ 2x + 1 y ≤ 2x – 2
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Answer:

Step-by-step explanation:

Given the two inequalities:

y \ge 2x + 1\\ y \le 2x - 2

To graph them, first of all, let us write their corresponding equations:

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We now find at least 2 points each which satisfy the equations to plot the graph.

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Let us take a point (1, 4) and check whether it satisfies the first inequality.

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Which is true.

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<em></em>

Let us take a point (1, 4) and check whether it satisfies the second inequality.

4 \le 2 \times 1 -2\\\Rightarrow 4 \le 0\ [\bold{False}]

So, The shaded region will be <em>opposite to point (1,4).</em>

Please refer to the attached graph for the answer.

<em>No solution exists for them because there is no common shaded region</em>.

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Step-by-step explanation:

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