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icang [17]
3 years ago
13

Question 1

Mathematics
1 answer:
natima [27]3 years ago
6 0

Answer:

Yes, her reasoning is correct

Step-by-step explanation:

Given the ratio:  109.2 : 6

Written in fractional form, we have:

109.2: 6=\dfrac{109.2}{6}

Now:

\dfrac{109.2}{6}=\dfrac{109.2}{6}X1, $  Let 1=\dfrac{10}{10}, \\\\=\dfrac{109.2}{6}X\dfrac{10}{10}\\\\=\dfrac{1092}{60}

Therefore, the student's reasoning is correct. In fact, as a check:

\dfrac{109.2}{6}=18.2\\\\\dfrac{1092}{60}=18.2

We would obtain the same result in both cases.

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Evaluate 6x + 11 when x = 7
nlexa [21]

Answer:

53

Step-by-step explanation:

To evaluate 6x + 11, we must substitute the value of x.

Since we know that x = 7, it is easier to evaluate the expression;

6x + 11

6(7) + 11

Since 6 is outside the parenthesis, we must multiply everything inside the parenthesis by 6;

6(7) + 11

42 + 11

When you add the two numbers you get:

53

4 0
3 years ago
Game Stop is selling used games in bundles. They have one bundle of 8 games for $52, and one bundle of 10 games for $62.50. Whic
natka813 [3]

Answer:

1

Step-by-step explanation:

3 0
2 years ago
In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
Ahat [919]

Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146

P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

6 0
3 years ago
Math help please? <3
Tomtit [17]
10m + 80 = P
where every month he gets 10, and for 6 months, he now has 60
plus the 80 he already has
so (10 * 6 ) + 80 = 140

7 0
3 years ago
Read 2 more answers
Help
alisha [4.7K]

Answer:

a. x^{2}  + 3y^{3}

b. 3y^{3} -6

c. 5x -3

d. -6t - 5

Step-by-step explanation:

When a number has the same variable as another, you can add or subtract them

So for the first one, you can do

5x^{2} -4x^{2} = 1x^{2}  = x^{2}

(But don't forget the 3y^{3}!)

So it is:

x^{2}  + 3y^{3}

Continue this process for the rest of them

7 0
2 years ago
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