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bonufazy [111]
3 years ago
5

Find the average rate of change from(0,1)

Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0
1 is the answer. I think
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Can anyone solve this for me? and show how you got that answer?
Mashutka [201]

53=20+x

Subtract 20 from 20 and 53

33=x

Hope this helps!

P.S.

Nice tab theme :P

6 0
3 years ago
What is it<br><br> −4(3/2x−12)=−15
Greeley [361]

Answer:

x = 21/2

Step-by-step explanation:

Step 1: Write equation

-4(3/2x - 12) = -15

Step 2: Solve for <em>x</em>

  1. Distribute -4: -6x + 48 = -15
  2. Subtract 48 on both sides: -6x = -63
  3. Divide both sides by -6: x = 21/2
3 0
3 years ago
Please answer ASAP. You begin with 1/2 scoop of ice cream. Since you're hungry, you ask the vendor for 2/7 more scoops of ice cr
katen-ka-za [31]

Answer:

9/56

Step-by-step explanation:

\frac{1}{2}  +  \frac{2 }{7}  -  \frac{5}{8 }  =  \frac{9}{56}

6 0
4 years ago
Read 2 more answers
Francine has a picture that is 5/2 its width. She wants to enlarge the picture to have an area of 490 in2. What will the dimensi
serg [7]

Answer:

Length = 2w

Width= w

2w times w= 241

2W^2=241

Divide by 2

W-^2=121

Sq rt each side

W-= 11 cuz 11 times 11=121

hope this helped

If it did, brainliest would be appreciated!

5 0
3 years ago
Two number cubes are rolled for two separate events:
andrew11 [14]

Answer:  \bold{P(B|A)=\dfrac{P(B\cap A)}{P(A)}=\dfrac{11}{30}}

<u>Step-by-step explanation:</u>

The probability of Event B given Event A = the intersection of Event A and B divided by the probability of Event A. (see below for the symbols)

P(B|A)=\dfrac{P(B\cap A)}{P(A)}

P(A) = (1, 6), (1, 5), (1, 4), (1, 3), (1, 2), (1, 1)

          (2, 6), (2, 5), (2, 4), (2, 3), (2, 2), (2, 1)

          (3, 6), (3, 5), (3, 4), (3, 3), (3, 2), (3, 1)

                    (4, 5), (4, 4), (4, 3), (4, 2), (4, 1)

                              (5, 4), (5, 3), (5, 2), (5, 1)

                                        (6, 3), (6, 2), (6, 1)

       = 30

P(B) = (1, 2), (2, 1)                                   sum = 3

          (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)    sum = 6

          (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)  sum = 9

          (6, 6)                                           sum = 12

                       

      = 12

P(A ∩ B) =  (1, 2), (2, 1)

                  (1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

                  (3, 6), (4, 5), (5, 4), (5, 4), (6, 3)

             = 11

7 0
4 years ago
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