The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444
Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
You need to create a chart like the one attached and put your own values in it. The teacher wants atleast 3 inputs and outputs but 4 or 5 is better. You first need to create a rule (EX: x+1=y)
Answer:
Its going by 3/8.
Step-by-step explanation:
the missing number is 1 5/8. I don't know if I'm right for the second
Answer:
y>-8
Step-by-step explanation:
The minimum range is found at the lowest point on the graph, which in this case, is -8. The point is not filled in, so -8 is not included in the range.
-hope it helps
Answer:
Check the image. I have solved every angle. hope this helps. pls give brainliest if possible.
