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2 years ago

3(y+9)=12y+13 how many differnt solutions does it have?

2 answers:

5 0

Choice B
Exactly 1 solution

Because:

First we must disrupte
3y+27=12y+13

Next we switch one number to the other side
27=9y+13

Now we must switch the other number
14=9y

Now we must solve by dividing 14 by 9

y=1.555

This is one solution, so we now have our answer.

Rudiy272 years ago

4 0

Answer:

Exactly 1 solution!

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$\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$

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$proj_ab = \dfrac{6}{130} * (5i+11j-2k)\\\\proj_ab = \frac{30}{130} i+\frac{11}{130} j-\frac{12}{130} k\\\\proj_ab = \frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\\\$

<em>Hence the projection of b unto a is expressed as </em> $\frac{3}{13} i+\frac{11}{130} j-\frac{6}{65} k\\$ <em></em>

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3 years ago

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son4ous [18]

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