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Mathematics

1 answer:

Verizon [17]3 years ago

5 0

20. x > 15
19. x $\leq$ -8
21. x $\geq$ 42

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If x does not equal 16 then 2x+10 does not equal 42

Lady bird [3.3K]

Answer:

The answer is

True

5 0

2 years ago

Read 2 more answers

The length of the diameter, d, of the circle is 16cm. Find the length of the radius, r, of the circle.

Anna71 [15]

The radius would be 8cm.

8 0

3 years ago

B -2(b - 2) simplified

BlackZzzverrR [31]

Answer:

b -2(b - 2)

b-2b+4

-b+4

4-b

5 0

2 years ago

The sides of a triangle are x,x+1,2x-1 and its area is x root 10. Find the value of x

Marianna [84]

You can use Heron's formula to solve this problem.

 $A= \sqrt{s(s-a)(s-b)(s-c)}$ , where A is the area; a,b,с are the sides; s is the semiperimeter of the triangle
 $s= \frac{a+b+c}{2}$

According to conditions:
a = x
b = x+1
с = 2x-1

Calculate the semiperimeter:
 $s= \frac{x+x+1+2x-1}{2} = \frac{4x}{2}=2x$

Now we can compose and solve the equation according to Heron's formula:
 $\sqrt{2x(2x-x)(2x-(x+1))(2x-(2x-1))}=x \sqrt{10} \\ \sqrt{2x(x)(2x-x-1)(2x-2x+1)}=x \sqrt{10} \\ \sqrt{2x^2(x-1)(1)}=x \sqrt{10} \\ \sqrt{2x^3-2x^2}=x \sqrt{10} \ \ \ |()^2 \\ 2x^3-2x^2=10x^2 \\ 2x^3-2x^2-10x^2=0 \\ 2x^3-12x^2=0 \ \ |:2 \\ x^3-6x^2=0 \\ x^2(x-6)=0 \\ \\ x^2=0 \\ x=0 \ \ \ \O \\ or \\ x-6=0 \\ x=6$

As a result, x = 6 is your answer.

I hope this helped.

7 0

2 years ago

What is the value of x? enter your answer into the box.

poizon [28]

Answer:

x = 27

Step-by-step explanation:

ΔBRD and ΔQCD are similar, hence the ratios of corresponding sides are equal, that is

$\frac{BD}{QD}$ = $\frac{RD}{CD}$