Answer:
Karen needs to spend $4.5 to buy new hair bands.
Step-by-step explanation:
Given:
Hair bands Karen have = 3
cost of 8 hair bands = $1
Total Hair bands she require = 39
Hence Number of of new hair bands require = Total Hair bands she require - Hair bands Karen have = 39 -3 = 36
we need to find how much money she need to spend to buy new hair bands.
cost of 8 hair bands = $1
Cost of 36 hair bands = money need to spend on hair bands
By using Unitary method we get;
Money spend on new hair bands = 
Hence,Karen needs to spend $4.5 to buy new hair bands.
Let m be mean
Mean= sum/ n
Mean= (1720+1687+1367+1614+1460+1867+1436) / 7
m= 11151 / 7
M= 1593
Mean= 1593
Standard deviation
|x-m|^2
For 1st: |1720-1593|^2=8836
For 2nd: |1687-1593|^2=10201
For 3rd: |1367-1593|^2=51076
For 4th: |1614-1593|^2=441
For 5th: |1460-1593|^2=1689
For 6th: |1867-1593|^2=75076
For 7th: |1436-1593|^2=24649
Summation of |x-m|^2 = 171968
Standard deviation sample formula is:
S.D = sqrt((summation of |x-m|^2) / n-1)
S.D=sqrt(171968/6)
S.D=sqrt(28661.33)
S.D=169.30
Standard deviation is 169.30
Answer:
25 inches
Step-by-step explanation:
1. Information that is needed to solve the problem;
The formula for the perimeter is:
2(a+b) = P
where "a" is the length and "b" is the width.
2. Solving the problem;
Substitute the given values into the formula;
2( 5 + b ) = 58
Inverse operations;
2 ( 5 + b ) = 58
/2 /2
5 + b = 29
-5 -5
b = 25
It would be n - 5
It’s saying 5 LESS than a number so 5 would be subtracted
Hope this helps!
Step-by-step explanation:
Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.
The standard error is SE = s/√n = 62.6/√50 = 8.85.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
180.56 ± 1.960 × 8.85
180.56 ± 17.35
(163, 198)
Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.
The standard error is SE = s/√n = 49.2/√50 = 6.96.
At 95% confidence, the critical value is z = 1.960.
Therefore, the confidence interval is:
152.96 ± 1.960 × 6.96
152.96 ± 13.64
(139, 167)
