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3 years ago

PLEASE HALP MEH

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

5 0

Answer:

A.The scale factor is 0.25 ⇒ <u>True</u>

B.The scale factor is 4 ⇒ <u>False</u>

Step-by-step explanation:

<u>See the attached figure.</u>

A dilation is a transformation that produces an image that is the same shape as the original, but is a different size.

A dilation that creates a smaller image is called a reduction.

As Shown, two right triangles, The first triangle is dilated to form the second triangle.

We can deduce that the second image is a smaller than the first triangle.

The hypotenuse of the first triangle = 4.4

The hypotenuse of the second triangle = 1.1

So, the scale factor = 1.1/4.4 = 11/44 = 1/4 = 0.25

<u>We will check the options:</u>

A.The scale factor is 0.25 ⇒ True

B.The scale factor is 4 ⇒ False

Oduvanchick [21]3 years ago

3 0

<h3><em>Answer: </em></h3><h3><em>1=true 2=wrong</em></h3><h3><em /></h3><h3><em>Step-by-step explanation: </em></h3><h3><em></em></h3><h3><em>1= the scale factor IS 0.25.</em></h3><h3><em>2=the scale factor is NOT 4.</em></h3><h2><em></em></h2><h2 />

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Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em /> $\displaystyle L = \sqrt{4kt - p}$

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, <em>add p to both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, <em>divide 4t by both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have <em>changed</em> the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

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