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GrogVix [38]
3 years ago
8

Why might it be beneficial for each firefly species to have its own unique light pattern?

Biology
2 answers:
AVprozaik [17]3 years ago
7 0
<span>Fireflies use the bioluminescence to attract mates for mating hence key in reproduction. Therefore, beetles from different species should have different lighting patterns so that they can only attract mates of the same species. This would avoid interspecies mating which would probably involved expending energy in produce nonviable offspring which is inefficient (hence will be unfavoured natural selection).    </span>
Neporo4naja [7]3 years ago
7 0
Every firefly species has their own unique light pattern, so they can attract mates of the same species. The flashing is helpful when they need to find each other in the dark. <span> Female fireflies choose their mates depending upon specific male flash pattern characteristics.</span>
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Dinobryon is a species of protozoa that reproduce asexually. How can this asexual reproduction be harmful to the species? A.They
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What does natural selection favor?​
ratelena [41]

Answer:

The mechanism that Darwin proposed for evolution is natural selection. Because resources are limited in nature, organisms with heritable traits that favor survival and reproduction will tend to leave more offspring than their peers, causing the traits to increase in frequency over generations.

The reason that natural selection is important is that it's the central idea, stemming from Charles Darwin and Alfred Russel Wallace, that explains design in nature. It is the one process that is responsible for the evolution of adaptations of organisms to their environment.

Explanation:

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3 0
3 years ago
The answer is 51.0 ml but can someone explain why please
professor190 [17]

Answer:

\boxed{\sf A. \ 51 \ mL}

Explanation:

Amount of water displaced by the sphere will be equal to the volume of complete sphere.

As the sphere completely sinks to the bottom of the cup.

We have been given;

Diameter of sphere (d) = 4.6 cm

So,

\sf Radius \:  of \:  sphere  \: (r) =  \frac{Diameter \:  of \:  sphere \: (d)}{2}  \\  \sf =  \frac{4.6}{2}  \\ \sf  = 2.3 \: cm

Volume of sphere (V):

\boxed{ \bold{V =  \frac{4}{3} \pi {r}^{3} }}

By substituting value of r we get:

\sf \implies V =  \frac{4}{3}  \times \pi \times  {(2.3)}^{3}  \\  \\  \sf \implies V =  \frac{4}{3}  \times 3.14 \times 12.167 \\  \\ \sf \implies V =    \frac{152.81752}{3} \\  \\   \sf \implies V =  50.94 \:  {cm}^{3}  \\  \\   \sf \implies V  \approx 51 \:  {cm}^{ 3}

1 cm³ = 1 mL

\therefore

V = 51 mL

So,

Water displaced by the sphere = 51 mL

6 0
3 years ago
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