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FrozenT [24]
2 years ago
5

99 pencils cost \$7.74$7.74dollar sign, 7, point, 74. Which equation would help determine the cost of 666 pencils? Choose 1 answ

er: Choose 1 answer: (Choice A) A \dfrac{6}{x} = \dfrac{9}{\$7.74} x 6 ​ = $7.74 9 ​ start fraction, 6, divided by, x, end fraction, equals, start fraction, 9, divided by, dollar sign, 7, point, 74, end fraction (Choice B) B \dfrac{x}{6} = \dfrac{9}{\$7.74} 6 x ​ = $7.74 9 ​ start fraction, x, divided by, 6, end fraction, equals, start fraction, 9, divided by, dollar sign, 7, point, 74, end fraction (Choice C, Checked) C \dfrac{9}{6} = \dfrac{x}{\$7.74} 6 9 ​ = $7.74 x ​ start fraction, 9, divided by, 6, end fraction, equals, start fraction, x, divided by, dollar sign, 7, point, 74, end fraction (Choice D) D \dfrac{6}{x} = \dfrac{\$7.74}{9} x 6 ​ = 9 $7.74 ​ start fraction, 6, divided by, x, end fraction, equals, start fraction, dollar sign, 7, point, 74, divided by, 9, end fraction (Choice E) E None of the above
Mathematics
1 answer:
balu736 [363]2 years ago
4 0

Answer:

\large \boxed{\text{A) } \dfrac{6}{x} = \dfrac{9}{\$7.74}}

Step-by-step explanation:

9 pencils cost $7.74

6 pencils cost x

The ratios are  

\dfrac{9}{6} = \dfrac{\$7.74}{x}

According to the alternendo property,

\dfrac{9}{6} = \dfrac{\$7.74}{x} \Rightarrow \dfrac{9}{\$7.74} = \dfrac{6}{x}\\\\\text{The correct answer is $\large \boxed{\mathbf{ \dfrac{6}{x} = \dfrac{9}{\$7.74}}}$}

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1) A rectangular storage container with an open top is to have a volume of 15 m 3 . The length of its base is four times the wid
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Answer:

  a) V = 4w²h

  b) SA = 4w² +10wh

  c) SA = 4w² +37.5/w

  d) C = 40w² +225/w

Step-by-step explanation:

The relevant formulas are ...

  V = LWH

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a) The length is 4 times the width, so the volume is ...

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b) The total surface area is the sum of the base area and the lateral area:

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c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...

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Then the surface area is ...

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d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:

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3 years ago
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