What is 7 times the 6th power?

Two buildings are facing each other on a road of width 12 metre . From the top of the first building, which is 10 metre high , t

Karo-lina-s [1.5K]

Answer:

$\displaystyle 10 + 12\sqrt{3}$ metres

Step-by-step explanation:

You are finding the height of the building with an angle of elevation, therefore we need to solve for EC to add it to BA [10 metres] and use TRIGONOMETRIC RATIOS to arrive at our conclusion. Just in case you have forgotten what they were, here they are:

$\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ$

We can now solve for EC:

$\displaystyle cot\:60 = \frac{12}{EC} → ECcot\:60 = 12 \\ \\ \frac{ECcot\:60}{cot\:60} = \frac{12}{cot\:60} → 12\sqrt{3} = EC$

OR

$\displaystyle tan\:60 = \frac{EC}{12} → 12tan\:60 = EC → 12\sqrt{3} = EC$

Now that you have solved for EC, you can now add it to your original 10 metres to get $\displaystyle 10 + 12\sqrt{3}$ metres. As a decimal, you would get $\displaystyle 30,78460969...$ metres. You can go ahead and round this off if necessary.

** The reason why the cotangent [or tangent] ratio was used was because EA is equivalent to DB by the definition of a rectangle. It has two pairs of parallel and congruent sides with four right angles. Plus, that is the adjacent side of the triangle, while EC is the opposite side of the triangle, so we knew our ratios were correct.

I am joyous to assist you at any time.

8 0

3 years ago

×>10 is a solution to which inequality a}×-7>3 b}×-7>3 c}x-7<3 d}x-7<3

NeX [460]

A) x - 7 > 3 |add 7 to both sides
x > 10

b) x - 7 > 3 |add 7 to both sides
x > 10

7 0

3 years ago

Find the product. 7/10 X 3/6

tiny-mole [99]

7 . 3
--- × ------
10. . 6

= 21
--------
60

= 7/20

4 0

3 years ago

Factor the binomial. 1 - q^4r^4

Ilia_Sergeevich [38]

Answer:

(1-q^2 r^2) x (1+q^2 r^2)

6 0

3 years ago

Henry wants to buy the same number of gift bags and bows. Gift bags are sold in packs of 6. Bows are sold in packs of 9. What is

Lynna [10]

Answer:

Henry will buy 18 gift bags and 18 bows in 3 packs of gift bags and 2 packs of bows.

Step-by-step explanation:

Least Common Multiple (LCM)

Is the smallest positive number that is a multiple of two or more numbers. To find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number.

Since Henry wants to buy the same number of gift bags and bows and they are sold in packs with different quantities, we must find the LCM between those numbers.

Gift bags are sold in packs of 6. Bows are sold in packs of 9.

List the prime factors of 6: 2,3

List the prime factors of 9: 3,3

Multiply: 2*3*3=18

The LCM is 18. This means Henry will buy 18 gift bags and 18 bows in 3 packs of gift bags and 2 packs of bows.

3 0

4 years ago