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Bingel [31]
3 years ago
5

Which characteristic of a relational database distinguishes it from a flat file?

Computers and Technology
1 answer:
kirill [66]3 years ago
5 0
C. several tables are linked together through common fields in a relational debase.


Correct answer
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Cutting of trees is bad or not bad​
olga_2 [115]
It is bad cutting tree :(
7 0
3 years ago
Read 2 more answers
Consider the classes below:
jeka57 [31]

Answer:

Hi!

The correct answer is d. Neither (a) nor (b) is true.

Explanation:

First, you have to know what the scripts intend to do, and they are counting from 1 to 10 in both cases.

Table of results of class TestA at end of each iteration:

[j = 0,  counter =  1]

[j = 10,  counter =  2]

[j = 20,  counter =  3]

[j = 30,  counter =  4]

[j = 40,  counter =  5]

[j = 50,  counter =  6]

[j = 60,  counter =  7]

[j = 70,  counter =  8]

[j = 80,  counter =  9]

[j = 90,  counter =  10]

Table of results of class TestB at end of each iteration:

[j = 10,  counter =  1]

[j = 9,  counter =  2]

[j = 8,  counter =  3]

[j = 7,  counter =  4]

[j = 6,  counter =  5]

[j = 5,  counter =  6]

[j = 4,  counter =  7]

[j = 3,  counter =  8]

[j = 2,  counter =  9]

[j = 1,  counter =  10]

That's why a) and b) are false.

Maybe you want to know why using pre increments on class TestB doesn't affect the loop. The reason is that when enters in a loop, first checks the test condition and takes the decision if true or false, and last executes the incrementation step.

7 0
3 years ago
Given a link with a maximum transmission rate of 18 Mbps. Only two computers, X and Y, wish to transmit starting at time t = 0 s
expeople1 [14]

Answer:

<em>Total time taken = 0.62 seconds </em>

Explanation:

<em>Transmission rate =  18 Mbps</em>

The size of file X winch will go fast= 11.73 MiB (Mebibyte) = 8.38 Mb(Megabit)  

The time it will take to transfer = File size / Transmission rate

                                                = 8.38 / 18 seconds

                                                = 0.46 seconds  

Mb in 1 KiB = 116.415  

The file Y that will go next has size = 340 Kib

                                                       = 340 / 116.41 Mb

                                                       = 2.92 Mb  

The time it will take to transfer = 2.92 / 18 seconds

                                                = 0.16

<em>Total time = Time taken for file X + Time taken for file Y </em>

<em>= 0.46 + 0.16 </em>

<em>= 0.62 </em>

<em />

3 0
4 years ago
Given the message size of 16Kb, packet size of 2Kb, speed of 4Kbps over 3 links, how much time, will it take the message to trav
ruslelena [56]

Answer:

5 seconds

Explanation:

Given that :

Message size = 16kb

Packet size = 2kb

Speed = 4kbps

Number of links = 3

The time taken is calculated using the formula :

[Number of packets + (Number of links - 1)] * (packet size / speed)

Number of packets = message size / packet size

Number of packets = 16kb / 2 kb = 8

Hence,

[Number of packets + (Number of links - 1)] * (packet size / speed)

(8 + (3 - 1)) * (2 / 4)

(8 + 2) * (1 /2)

10 * 1/2

= 5 seconds

6 0
3 years ago
Im a beginner programmer. what languages should i learn and how do i get better
anyanavicka [17]

Answer: Python, Coding, JavaScript and there's more out there but it's been a while since I have taken Tech classes in a while!

Explanation: I recommend you use typing.com and code.org for coding! I don't know how else to answer this question but this was all I could say!

3 0
2 years ago
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