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Fudgin [204]
4 years ago
15

Find the distance between the points (3,-5) and (3,-2).

Mathematics
1 answer:
iren [92.7K]4 years ago
3 0

Answer:

3 units

Step-by-step explanation:

Distance between two points (x1,y1) and (x2,y2) on coordinate plane is given by

distance = \sqrt{(x1-x2)^2 +(y1-y2)^2  }

Given points in the problem are (3,-5)  and (3,-2).

Thus distance between points (3,-5)  and (3,-2).

distance = \sqrt{(x1-x2)^2 +(y1-y2)^2  }\\=>distance = \sqrt{(3-3)^2 +(-5-(-2))^2  }\\=>distance = \sqrt{(0)^2 +(-5+2)^2  }\\\\=>distance = \sqrt{0 +(-3)^2  }\\\\=>distance = \sqrt{9  }\\=>distance = 3

Distance between points (3,-5)  and (3,-2) is 3 units

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The Area of rectangle = 80 unit².

<h3>What is Area of rectangle?</h3>

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from figure (a)

DE= 40/8 = 5

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Now, from figure (b)

CD= 24/12= 2

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brainly.com/question/237997

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7 0
2 years ago
Identify and solve the inequality that represents how many $20 bills, n, you can withdraw from the account without going below t
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Answer:

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Step-by-step explanation:

Given

Balance = \$230.00

Minimum = \$100

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Required

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Let the number of dollars be represented by n

<em>If 1 withdrawal is $20 bill</em>

<em>n withdrawals would be $20n bills</em>

The total withdrawal and the minimum balance must be less than or equal to the available balance.

So, this gives

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Answer:

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