Question

Find the distance between the points (3,-5) and (3,-2).

Answer 1

Answer:

3 units

Step-by-step explanation:

Distance between two points (x1,y1) and (x2,y2) on coordinate plane is given by

distance = $\sqrt{(x1-x2)^2 +(y1-y2)^2 }$

Given points in the problem are (3,-5)  and (3,-2).

Thus distance between points (3,-5)  and (3,-2).

$distance = \sqrt{(x1-x2)^2 +(y1-y2)^2 }\\=>distance = \sqrt{(3-3)^2 +(-5-(-2))^2 }\\=>distance = \sqrt{(0)^2 +(-5+2)^2 }\\\\=>distance = \sqrt{0 +(-3)^2 }\\\\=>distance = \sqrt{9 }\\=>distance = 3$

Distance between points (3,-5)  and (3,-2) is 3 units